Can someone help on this please

Can someone help me

dexar [7]

Answer:B:yes

Step-by-step explanation:

7 0

3 years ago

Can you help me to solve this

stealth61 [152]

Answer:

$\text{Triangle 1:}\\\\x=30\sqrt{2},\\\\\text{Triangle 2:}\\x\approx 36.18,\\?\approx12.37$

Step-by-step explanation:

*Notes (clarified by the person who asked this question):

-The triangle on the right has a right angle (angle that appears to be a right angle is a right angle)

-The bottom side of the right triangle is marked with a question mark (?)

Triangle 1 (triangle on left):

Special triangles:

In all 45-45-90 triangles, the ratio of the sides is $x:x:x\sqrt{2}$ , where $x\sqrt{2}$ is the hypotenuse of the triangle. Since one of the legs is marked as $30$ , the hypotenuse must be $\boxed{30\sqrt{2}}$

It's also possible to use a variety of trigonometry to solve this problem. Basic trig for right triangles is applicable and may be the simplest:

$\cos 45^{\circ}=\frac{30}{x},\\x=\frac{30}{\cos 45^{\circ}}=\frac{30}{\frac{\sqrt{2}}{2}}=30\cdot \frac{2}{\sqrt{2}}=\frac{60}{\sqrt{2}}=\frac{60\cdot\sqrt{2}}{\sqrt{2}\cdot \sqrt{2}}=\frac{60\sqrt{2}}{2}=\boxed{30\sqrt{2}}\\$

Triangle 2 (triangle on right):

We can use basic trig for right triangles to set up the following equations:

$\cos 20^{\circ}=\frac{34}{x},\\x=\frac{34}{\cos 20^{\circ}}\approx \boxed{36.18}$ ,

$\tan 20^{\circ}=\frac{?}{34},\\?=34\tan 20^{\circ}\approx \boxed{12.37}$

We can verify these answers using the Pythagorean theorem. The Pythagorean theorem states that in all right triangles, the following must be true:

$a^2+b^2=c^2$ , where $c$ is the hypotenuse of the triangle and $a$ and $b$ are two legs of the triangle.

Verify $34^2+(34\tan20^{\circ})^2=\left(\frac{34}{\cos20^{\circ}}\right)^2\:\checkmark$

3 0

2 years ago

Find the measure of QP PLEASE SHOW WORK

KIM [24]

the measurement of QP=8 CM

8 0

2 years ago

Find the surface area of the composite figur

elena-14-01-66 [18.8K]

By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.

<h3>What is the surface area of a composite figure formed by two right prisms?</h3>

According to the image, we have a composite figure formed by two right prisms. The surface area of this figure is the sum of the areas of its faces, represented by squares and rectangles:

A = 2 · (4 cm) · (5 cm) + 2 · (2 cm) · (4 cm) + (2 cm) · (5 cm) + (3 cm) · (5 cm) + (5 cm)² + 4 · (3 cm) · (5 cm)

A = 166 cm²

By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

3 0

1 year ago

9y-(2y-3)=5(y-2)+2y I’m confused on how to do this kind of problem.

ira [324]

Answer:

use pemdas

Step-by-step explanation:

parentheses exponents multiplacation divide add subtract

4 0

2 years ago