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AnnyKZ [126]
3 years ago
14

Solve the system using the substituiton method branliest offered 3x-7y=10 x-4y=5

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0
Hi there!

To solve this problem using substitution, we need to set x equal to a value and substitute it into the other equation.

Since
x - 4y = 5,
x = 5 + 4y

3x - 7y = 10
3(5 + 4y) - 7y = 10
15 + 12y - 7y = 10
15 + 5y = 10
5y = -5
y = -1

Now that we know y is -1, we can substitute it back into the equation to find x:

y = -1
x - 4y = 5
x - 4(-1) = 5
x - (-4) = 5
x + 4 = 5
x = 1

So, your answers are x = 1 and y = -1.

Hope this helps!
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Please help!
agasfer [191]
Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)

We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.

6x+3y=-12

Now just subtract it from the other equation.

6x+3y=-12
5x+3y=-6

***x=-6***

Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.

2(-6)+y=-4
-12+y=-4
y=8

Brainliest my answer if it helps you out?
4 0
3 years ago
Read 2 more answers
Solve:<br> 0.03g - (2g + 3) = 1.8
wel

Answer:

-2.43655

Step-by-step explanation:

3 0
3 years ago
How do you make 1 1-2/1-6-7/8 a mixed number
AveGali [126]

Answer:

17/8

Step-by-step explanation:

2/1=2

11-2-6-7/8

9-6-7/8

3-7/8

24/8-7/8

17/8

8 0
3 years ago
A purchaser of electric relays buys from two suppliers, A and B. Supplier A supplies two of every three relays used by the compa
inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

P(X\leq38)=P(X

5 0
3 years ago
Need help !!!! How to solve this problem
ss7ja [257]

N = 15

First you would add 5 to both sides.

Then you would Multiply 3 on both sides to get N by itself

By multiplying 3 x 5 it gives you 15

So N = 15

5 0
3 years ago
Read 2 more answers
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