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AnnyKZ [126]
3 years ago
14

Solve the system using the substituiton method branliest offered 3x-7y=10 x-4y=5

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0
Hi there!

To solve this problem using substitution, we need to set x equal to a value and substitute it into the other equation.

Since
x - 4y = 5,
x = 5 + 4y

3x - 7y = 10
3(5 + 4y) - 7y = 10
15 + 12y - 7y = 10
15 + 5y = 10
5y = -5
y = -1

Now that we know y is -1, we can substitute it back into the equation to find x:

y = -1
x - 4y = 5
x - 4(-1) = 5
x - (-4) = 5
x + 4 = 5
x = 1

So, your answers are x = 1 and y = -1.

Hope this helps!
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Answer:

\boxed{-3(x+3)(x^2-6x+10)}

Step-by-step explanation:

Hello,

As the polynomial has only real coefficients, it means that 3-i is a zero too, because we apply the Conjugate Zeros Theorem.

It means that we can write the expression as below, k being a real number that we will have to identify.

k(x+3)(x-3-i)(x-3+i)=k(x+3)((x-3)^2-i^2)\\\\=k(x+3)(x^2-6x+9+1)\\\\=k(x+3)(x^2-6x+10)

And for x = 0, y = -90 so we can write

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Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Answer:

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Read 2 more answers
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