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yanalaym [24]
2 years ago
5

A torsion balance has a sensitivity requirement (SR) of 6.0 mg. What is the MWQ of this balance if the maximum error permitted i

n using it is 4.2%? [round answer to a whole number]
Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

MWQ is 143 mg

Step-by-step explanation:

given data

sensitivity requirement (SR) =  6.0 mg

maximum error = 4.2%

to find out

MWQ

solution

we know here MWQ formula that is

MWQ = \frac{sensitivity requirement}{error}     ................1

so here error is 4.2 % = 0.042

put here all these value in equation 1 we get

MWQ = \frac{sensitivity requirement}{error}

MWQ = \frac{6}{0.042}

MWQ = 142.857 mg

so MWQ is 143 mg

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The fifth grade teachers took their classes on a field trip to museum first group had 25 students and two teachers and cost $97.
iren [92.7K]

Answer:


Step-by-step explanation:

S=student cost; T=teacher cost

.

32S+3T=$127 . Multiply this by 2.

64S+6T=$254 Subtract this below

.

25S+2T=$97.50 . Multiply this by 3.

75S+6T=$292.50

64S+6T=$254 . Subtract this (from above.)

.

11S=$38.50

S=$3.50

ANSWER 1: Student tickets cost $3.50.


.

32S+3T=$127

32($3.50)+3T=$127

$112+3T=$127

3T=$15

T=$5.00

ANSWER 2: Teacher tickets cost $5.00.

.

CHECK:

25S+2T=$97.50

25($3.50)+2($5.00)=$97.50

$87.50+$10.00=$97.50

$97.50=$97.50


4 0
3 years ago
Which of the following is the equation of a line parallel to the line y=3x+2, passing through the point (10,1)?
anygoal [31]
k:y=3x+2\\l:y=mx+b\\\\k\ ||\ l\iff m=3\\\\l:y=3x+b;\ (10;\ 1)\\\\3\cdot10+b=1\\30+b=1\\b=1-30\\b=-29\\\\l:y=3x-29\to 3x-y=29\\\\Answer:A.
7 0
3 years ago
How many different 10-letter words (real or imaginary) can be formed from the letters of the word LITERATURE?
nordsb [41]

Answer:

The number of words that can be formed from the word "LITERATURE" is 453600

Step-by-step explanation:

Given

Word: LITERATURE

Required: Number of 10 letter word that can be formed

The number of letters in the word "LITERATURE" is 10

But some letters are repeated; These letters are T, E and R.

Each of the letters are repeated twice (2 times)

i.e.

Number of T = 2

Number of E = 2

Number of R = 2

To calculate the number of words that can be formed, the total number of possible arrangements will be divided by arrangement of each repeated character. This is done as follows;

Number of words that can be formed = \frac{10!}{2!2!2!}

Number of words = \frac{10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1}{2 * 1 * 2 * 1 * 2 * 1}

Number of words = \frac{3628800}{8}

Number of words = 453600

Hence, the number of words that can be formed from the word "LITERATURE" is 453600

8 0
3 years ago
Simplify <br><img src="https://tex.z-dn.net/?f=%285%20%2B%201%29%20%5E%7B2%7D%20%20-%20%2811%20%2B%203%20%5E%7B2%7D%20%29%20%5Cd
Elodia [21]

Answer:

31

Step-by-step explanation:

Evaluate following the order set out in the acronym PEMDAS

That is parenthesis, exponents, multiplication, division, addition, subtraction

Given

(5 + 1)² - (11 + 3² ) ÷ 4

= 6² - (11 + 9) ÷ 4

= 36 - 20 ÷ 4 ← division before subtraction

= 36 - 5

= 31

6 0
3 years ago
7. 2(a + 1) = 2(2-3)​
sdas [7]

Answer:

#YOUCHEAPSUCKA

the answers is = -2

Step-by-step explanation:

4 0
3 years ago
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