Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
I’m pretty sure the answer is B
(Hope this helps!!) Can I pls have brainliest??
Answer:
B. 8 x 10^3
Step-by-step explanation:
1.6 x 10^5 / 0.2 x 10^2
= 160 000 / 20
= 8 000
You can write this as 8 x 10^3
Sum of infinite series of a GS is a1 / (1-r)
so here it is 65 / (1 - 1/6) = 65 / 5/6 = 65*6 / 5 = 78 answer
June: 30-6=24
July: 31
August:31
September:30
October: 8
Total=24+31+31+30+8=124 days
Discount period:
The period of time between the date a bill of exchange is drawn and the date on which payment is due.
So discount period = 200-124=76 days
