Answer:
5.9 years.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation 
In this question:
Mean of the population is 
If a sampling distribution is created using samples of the ages at which 69 children begin reading, what would be the mean of the sampling distribution of sample means?
By the Central Limit Theorem, the same population mean, of 5.9 years.
Answer:
a.) (1, 6)
Step-by-step explanation:
graph
Answer:
(a+6)2=49 (use the distributive property and multiply 2 by everything left side
2a +12=49 (subtract 12 from both sides to isolate the a-term)
2a = 37 (divide both sides by 2 to get a alone)
a= 18.5 (this is your answer)
Step-by-step explanation:
I hope this helps :)