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3 years ago

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WXY is an isosceles triangle with line WX congruent to line WY. if WX is 3 more than four times x, XY is 7 less than five times

x, and WY is 66 less than seven times x, find x and the measure of each side.

1 answer:

iragen [17]3 years ago

5 0

WX = WY
4x+3 = 7x-66
3x = 69
x = 23
WX = 95 = WY
XY = 5*23-7 = 108

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Which graph represents 2x-5y<15?

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There’s no pictures

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3 years ago

-6+8x=-38<br> What is the answer and explain how you got it step by step

Anarel [89]

-6 +8x = -38
8x = -32
x = -4
I did this by first adding 6 to both sides to get 8x by itself. I then divided by 8 to get x by itself. I remembered to use the - - + rule (Two negatives make a positive, a positive and a negative make a negative). Hope this helps!

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3 years ago

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An open box is to be made from a square piece of cardboard, 18 inches by 18 inches, by removing a small square from each corner

seraphim [82]

The dimension of the box of the greatest volume that can be constructed in this way is 12x12x3 and the volume is 432.

<h3>How to solve the dimension?</h3>

Let x be the side of the square to remove. Then the volume of the box is:

V(x) = (18 - 2x)² * x = 324x - 72x² + 4x³

To find the maximum volume, differentiate and set it to 0:

V'(x) = 324 - 144x + 12x²

0 = x² - 12x + 27

0 = (x - 9)(x - 3)

x = 3 or 9

When x = 3,

V"(x) =-144+24x

V"(3) =-144+72=-72<0

so volume is maximum at x=3

Therefore the box is 12x12x3 and the volume is 432.

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2 years ago

Identify the property used in each step of solving the inequality . 7x+4<46

ExtremeBDS [4]

For this case we have the following inequality:

$7x + 4$

Subtracting 4 from both sides of the inequality we have:

$7x$

Dividing between 7 on both sides of the inequality we have:

$x$

Thus, the properties used were:

Subtraction property

Division property

Answer:

Subtraction property

Division property

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3 years ago

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A researcher collects data on the number of times race horses are raced during their careers. The veterinarian finds that the av

vesna_86 [32]

Answer:

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

Step-by-step explanation:

<u>Explanation</u>:-

The veterinarian finds that the average number of races a horse enters is 15.3

The mean of the sample x⁻ = 15.3

Given standard deviation of the sample 'S' = 6.8

Given sample size 'n' = 25

Degrees of freedom = n-1 =25-1 =24

The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance

<u> 95% confidence for µ, the average number of times a horse races</u>

<u></u> $(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$ <u></u>

<u></u> $(15.3- 2.064 \frac{6.8}{\sqrt{25} } , 15.3 + 2.064\frac{6.8}{\sqrt{25} } )$ <u></u>

(15.3 - 2.80704 ,15.3 +2.80704)

(12.493 , 18.107)

<u>Conclusion</u>:-

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

3 0

3 years ago