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padilas [110]
3 years ago
13

What are the restrictions for (x^2+10x+25)/(x^2-3x-28) 0,14 -4,7 0,7 4,7

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0
The answer is -4,7

The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
(X - 7)(x + 4); next set each set of parentheses equal to 0;
x - 7 = 0; so x=7 is one value
x + 4 = 0; so x=-4 is the other
Remember, x = 7 and x= -4 make the denominator zero, which is a "restriction" because you can't divide by zero.
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(Before you answer I am looking for how I do it. I have the answers but I need to know an equation to do this instead of using l
Tema [17]

Answer:

14 and 16.

Step-by-step explanation:

We know that two consecutive even numbers is 30.

Let's let n be <em>any number</em>.

Then the first <em>even</em> number must be 2n.

This is because n can be any number, either even or odd. However, if we multiply it by 2, this <em>ensures</em> that 2n is even. Remember that any number multiplied by 2 yields an even number.

Therefore, the consecutive even number will be (2n+2). Not (2n+1), because that gives an odd number.

We know that they sum to 30. So, we can write the following equation.

(2n)+(2n+2)=30

And we solve from there:

4n+2=30\\\Rightarrow4n=28\\\Rightarrow n=7

So, the value of n is 7.

Therefore, the first even number is 7(2)=14.

And the consecutive even number is 16.

Edit: Typo

7 0
2 years ago
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inysia [295]

Answer:

Step-by-step explanation:

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Karolina [17]
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3 years ago
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ivanzaharov [21]

Answer:

256

Step-by-step explanation:

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4*64=<u>256</u>

This equation is also known as 4⁴

6 0
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