The monthly starting salaries of students who receive an MBA degree have a population standard deviation of $120. What sample si
ze should be selected to obtain a .95 probability of estimating the population mean monthly income within a margin of $20? [sample size]
1 answer:
Answer:
138
Step-by-step explanation:
Population standard deviation =
.95 probability of estimating the population mean monthly income within a margin of $20
So, Significance level = 1-0.95 = 0.05
α =0.05
Margin error = 20
Z at 0.05 = 1.96
So, n = 138
Hence sample size should be 138 selected to obtain a .95 probability of estimating the population mean monthly income within a margin of $20
You might be interested in
Need more to go on please, Thank You have a nice day!
Answer: You could use a translation since the shape is maintaining its orientation and size. All it’s doing is moving to the right.
The area is 1 foot multiplied by the number you're looking for, so to get from 1 to 300 you multiply by 300ft, which is the answer
Answer:
form 1 question????????