In a voltaic cell , the anode electrons and is oxidized , while the cathode electrons and is reduced.
Answer:
The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):
pOH= -log [OH-]
A solution has a pOH of 4.90. Replacing in the definition of pOH:
4.90= -log [OH-]
Solving:
-4.90= log [OH-]
1.26*10⁻⁵ M= [OH-]
<u><em>The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.</em></u>
Volume = ?
Molarity (M) = 1.00 x 10⁻² M
moles (n) = 3.00 x 10⁻¹ mol
V = n / M
V = 3.00 x 10⁻¹ / 1.00 x 10⁻²
V = 30 L
Answer:
Explanation: IE1 increases from left to right across a period. However, since Na has only one valence electron, IE2 for Na involves the removal of a core electron − requiring significantly more energy.
