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Oksi-84 [34.3K]
3 years ago
9

Aspirin, like many pharmaceutical drugs, can access the cell because it is a weak acid. This occurs because Choose one: A. it is

carried by water during osmosis. B. it is a small uncharged molecule. C. it disrupts the membrane enough to squeeze through. D. as a weak acid it can cross the membrane when in its uncharged form.
Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

Correct answer is (D). as a weak acid it can cross the membrane when in its uncharged form.

Explanation:

Aspirin (acetylsalicylic acid, ASA) is an analgesic and anti-inflammatory agent use in the treatment of gentle to moderate pain, inflammation and fever. It is absorb in the stomach and intestine in an unchanged form.

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Determine the number of atoms in 41.0 grams of calcium, Ca. (The mass of one mole of calcium is 40.08 g.)
Dovator [93]

Hi there!

Let me know if you have questions about my answer:

6.15 × 10²⁴

Explanation:

To find the number of atoms, divide the mass of calcium (m) by its molar mass (MM). This will give you the number of moles of calcium (n).

n = m/MM            Start with a formula

=\frac{41.0g}{40.08g/mol}             Substitute values from the question

= \frac{41.0g*1mol}{40.08g}             Simplify

= \frac{41.0mol}{40.08}                 Cancel out the units "g"

= 1.022...mol          Number of moles of calcium, with 4 significant figures

Then, multiply the number of moles of calcium (n) by Avogadro's number (N_{A}) to find the number of calcium atoms.

Number.of.Ca=n*N_{A}      Start with a formula

= 1.022mol*\frac{6.022*10^{23}Ca}{1mol}      Substitute values from the question

= \frac{1.022mol*6.022*10^{23}Ca}{1mol}           Simplify

= 1.022*(6.022*10^{23}Ca)     Cancel out the units "mol"

= 6.154*10^{24} Ca                   Multiply, leave one extra digit to help round. "4" tells you to round down.

= 6.15*10^{24} Ca                     Final answer to 3 significant figures*

*When multiplying and dividing numbers, your final answer will have the same number of significant figures as the number with the least number of significant figures in the question.

40.08 has 4 significant figures. 41.0 has 3 significant figures. So, you want 3 significant figures in your final answer.

I hope this helps!

Learn more about Avogadro's number here:

brainly.com/question/1445383

Check out another answer that uses significant figures:

brainly.com/question/3721164

7 0
2 years ago
What is the mass number of a carbon isotope with 10 neutrons
Korvikt [17]

Answer:

16 because carbon atom having usual 6 neutron have a mass number of 12 and that with 7 neutron has mass number of 13

4 0
3 years ago
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Water carries helpful nutrients to new areas,
den301095 [7]

Answer:

Positive Flood I believe

8 0
3 years ago
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Represent the formation of cations for the following metal atoms using electron dot structures. (a) Al (b) Sr (c) Ba​
vagabundo [1.1K]

the formation of cations by using electron dot structures are :

a) Al

.

Al .    losing the three valence electrons makes the Al³⁺

.

b) Sr :  

  Sr :  losing the two valence electrons makes Sr²⁺

c) Ba

: Ba , losing the two valence electrons makes it Ba²⁺

A Lewis electron dot diagram is a representation of the valence electrons of an atom that employments specks around the image of the element. The number of dots equals the number of valence electrons within the molecule. These dots are arranged to the right and left and over and underneath the symbol, with no more than two dots on a side. Cations are the positive ions shaped by the loss of one or more electrons. The foremost commonly shaped cations of the representative elements are those that include the loss of all of the valence electrons.

To know more about the lewis electron dot diagram refer to the link brainly.com/question/14191114?referrer=searchResults.

#SPJ9

3 0
1 year ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
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