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2 years ago

8

Plot each pair of points in the Cartesian plane and solve for the distance between them. Write your answer on a separate one who

le graph paper. ( 15 points) 1. A(0,8) and B(5,5) 2. C(3, 1) and D(0,-2) 3. EC -6,3) and F(-6,-2)

1 answer:

sammy [17]2 years ago

8 0

Answer:

hame naghi ahta

Step-by-step explanation:

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The buying price is $10 and the markup is 80% of the buying price what is the markup?

KATRIN_1 [288]

$10 * .8 = $8 that's it

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2 years ago

Sixty-eight percent of adults in a certain country believe that life on other planets is plausible. You randomly select five adu

Pavlova-9 [17]

Answer:

Mean = 3.4

Variance = 1.088

Standard deviation = 1.0431

Step-by-step explanation:

$P=0.68\\ \\N=5$

The mean of a binomial distribution with parameters N (the number of trials) and p (the probability of success for each trial) is $m=N\cdot p$

Thus,

$m=5\cdot 0.68=3.4$

The variance of the binomial distribution is $s^2=Np(1-p)$ , where $s^2$ is the variance of the binomial distribution, so

$s^2=5\cdot 0.68\cdot (1-0.68)=3.4\cdot 0.32=1.088$

The standard deviation $s$ is the square root of the variance $s^2,$ so

$s=\sqrt{1.088}\approx 1.0431$

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2 years ago

Help me pleaseee!!!!!!!!!!!!!!!!!!!!

Stolb23 [73]

You have to square the binomial.
(x^3 + 4y) (x^3 + 4y)
Using FOIL:
x^9 + 4(x^3)y + 4(x^3)y + 16y^2
x^9 + 8(x^3)y + 16y^2

You could also use the formula: (a+b)^2 = (a^2 + 2ab + b^2).

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3 years ago

The prices of pants at a large clothing store chain are skewed left with a mean of $32 and a standard deviation of $20. The mana

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2 years ago

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Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7

kozerog [31]

Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

<u>Given quadratic equation</u>:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

$\implies (x-3)^2-2+2=0+2$

$\implies (x-3)^2=2$

$\implies \sqrt{(x-3)^2}=\sqrt{2}$

$\implies x-3= \pm\sqrt{2}$

$\implies x-3+3= 3\pm\sqrt{2}$

$\implies x= 3\pm\sqrt{2}$

Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

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8 months ago

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