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xxMikexx [17]
3 years ago
5

Which number is an irrational number​

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0

Answer:7 is an irrational number.

Step-by-step explanation: it can be expressed as the quotient of two integers: 7÷ 1.

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The graph shows two lines, A and B.
muminat
Ur 1 solution is where the lines intersect, which is (1,4)
7 0
4 years ago
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A surveyor wants to know the length of a tunnel built through a mountain. According to his equipment, he is
MrMuchimi

Answer:

Length of the tunnel is 51.7 meters

Step-by-step explanation:

We are given that,

The surveyor is located 54 meters from one entrance at an angle of 56°.

The surveyor is located 31 meters from one entrance at an angle of 13°.

Let the length of the tunnel = x meters

So, using the law of cosines, we get,

x^2=54^2+31^2-2\times 54\times 31\times \cos 69

i.e. x^2=2916+961-3348\times 0.3584

i.e. x^2=3877-1199.9

i.e. x^2=2677.1

i.e. x = 51.7 meters

Hence, the length of the tunnel is 51.7 meters

5 0
3 years ago
What is the answer to this. Correct answer will get brainliest.
kvv77 [185]
The answer should be -116
7 0
3 years ago
An equation of a hyperbola is given.
siniylev [52]

Answer:

a)

The vertices are \left(3,\:0\right),\:\left(-3,\:0\right).

The foci are \left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right).

The asymptotes are y=2x,\:y=-2x.

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1 is the standard equation for a right-left facing hyperbola with center \left(h,\:k\right).

a)

The vertices\:\left(h+a,\:k\right),\:\left(h-a,\:k\right) are the two bending points of the hyperbola with center \:\left(h,\:k\right) and semi-axis a, b.

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 and vertices \left(3,\:0\right),\:\left(-3,\:0\right).

For a right-left facing hyperbola, the Foci (focus points) are defined as \left(h+c,\:k\right),\:\left(h-c,\:k\right) where c=\sqrt{a^2+b^2} is the distance from the center \left(h,\:k\right) to a focus.

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 c=\sqrt{3^2+6^2}= 3\sqrt{5} and foci \left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)

The asymptotes are the lines the hyperbola tends to at \pm \infty. For right-left hyperbola the asymptotes are: y=\pm \frac{b}{a}\left(x-h\right)+k

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 and asymptotes

y=\frac{6}{3}\left(x-0\right)+0,\:\quad \:y=-\frac{6}{3}\left(x-0\right)+0\\y=2x,\:\quad \:y=-2x

b) The length of the transverse axis is given by 2a. Therefore, the lenght is 6.

c) See below.

4 0
4 years ago
You bought a magazine for $2 and some erasers for $4 each. You spent a total of $22. How many erasers did you buy?
Natalija [7]

Answer:

You bought 5 erasers.

Step-by-step explanation:

You have the erasers sold for 4 dollars each and you have only 20 dollars left over to buy erasers so you divide 20 by 4 to get 5

3 0
4 years ago
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