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Agata [3.3K]
3 years ago
14

Michelle has 21 ⅙ cups of flour in a container. She uses 6 ⅚ cups of flour to make 5 loaves of bread. How much flour does Michel

le have left in the container?
Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0
It should be about -13 cups
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Find the domain of the function f of x equals the cube root of the quantity x plus three, minus one.
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<span>The domain of the function f of x equals the cube root of the quantity x plus three, minus one would be:

ALL REAL NUMBERS 

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An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be
VLD [36.1K]
I don't like trying all of them so I will make up my own which will probably be in the answers 
so equation is
f(x)=pay
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they seem to be increasing in 20 increments so therefor the pay is linked to hours times 20 so that measn that every hour he works, he gets 20 dollars
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the answe ris f(n+1)=f(n)+20

5 0
3 years ago
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The mean temperature for the first 7 days in January was 3 °C.
weeeeeb [17]

m = \frac{a_1 + a_2 + ... + a_n}{n}\\~\\m = \frac{3 * 7 + 2}{8} = \frac{21 + 2}{8} = \frac{23}{8} = 2,875

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Zina [86]
I'm positive that it is one 

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Find the sum of a finite geometric series. The Smiths spent $2,000 on clothes in a particular year. If they increase the amount
boyakko [2]

\bf \stackrel{\textit{first year}}{2000}~~,~~\stackrel{\textit{second year}}{2000+\stackrel{\textit{10\% of 2000}}{\frac{2000}{10}}}\implies 2200

now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus \bf 110\%\implies \cfrac{110}{100}\implies 1.1.

so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1}  \right)\\\\\\S_4=2000(4.641)\implies S_4=9282

7 0
3 years ago
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