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Viktor [21]
3 years ago
13

PLEASE HELP ME THIS IS URGENT

Mathematics
2 answers:
Sveta_85 [38]3 years ago
7 0
D is what i got. because that is the only possible answer.
Kryger [21]3 years ago
5 0
It a because been doing that for a long time
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Which sign should be used for the following equation? 0.452 _______ 0.712 < > ≤ ≥
ZanzabumX [31]

Answer:

<

Step-by-step explanation:

0.4<0.7

4 is smaller than 7 so the sighn points to 0.7

7 0
2 years ago
Can you help me find the value of x and y. I am very confused.
Monica [59]
Hello,
Let's assume top left  corner: A
top right corner : B
Bottom right corner: C
Bottom left corner :D

M= middle of [CD]

ABM is a triangle rectangular isocel:

(3√2)²+(3√2)²=y²
==>y²=2*9*2
==>y²=36
==>y=6

The triangle BCM is rectangular with MB=3√2, MC=y/2=3
x²+3²=(3√2)²
==>x²=9*2-9
==>x²=9
==>x=3

8 0
3 years ago
Select all expressions that are equivalent to 4 (3x+2)
Hunter-Best [27]

Answer:

88.77

Step-by-step explanation: 88.99 x 44.66 is the answer also 24 plus88

3 0
3 years ago
Como se hace -8n+7=31
velikii [3]
-8n+7=31
-8n+7-7=31-7
-8n=31-7
-8n=24
-8n÷(-8)=24÷(-8)
n=24÷(-8)
n=-24÷8
n=-3
8 0
3 years ago
On September 25, 2011 Michael Vick, the quarterback for the Philadelphia Eagles broke his non-throwing hand in a football game a
miskamm [114]

Answer:

D. We are 95% confident that between about 22% and 28% of ESPN Viewers thought the Eagles would still win the division.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the population proportion.  The population is made up of ESPN viewers.

The sample proportion is p=0.25.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.25*0.75}{914}}\\\\\\ \sigma_p=\sqrt{0.00021}=0.014

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.014=0.028

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.25-0.028=0.222\\\\UL=p+z \cdot \sigma_p = 0.25+0.028=0.278

The 95% confidence interval for the proportion of ESPN viewers  is (0.222, 0.278) or (22.2%, 27.8%).

7 0
3 years ago
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