A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer: X" ( -3,2) Y" (-1,0) Z" (1,6)
Step-by-step explanation:
Answer:
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Answer:
40
Step-by-step explanation:
(2/5)*n - 6 = 10 Add 6 to both sides
(2/5)*n - 6 + 6 = 10 + 6 Combine
(2/5)*n = 16 Multiply both sides by 5/2
(5/2)(2/5)n = 16*(5/2)
n = 80 / 2
n = 40
