6(3x+8)+32+12x
6•3x+6•8+32+12x
18x+48+32+12x
30x+48+32
30x/80
0.375
Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm
Width=scale÷Actual = 1/50 = 1×50 = 50cm
Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2
Area of the electronic board is 9000 cm2
Answer: (-∞, 65/3)
Step-by-step explanation:
<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>
The total area available for cars to park will be 858m².
<h3>How to calculate the area?</h3>
The area of the parking lot will be:
= 78 × 19
= 1482m²
The area of aisle will be:
= 8 × 78
= 624m²
The available area will be:
= 1482m² - 624m²
= 858m².
The compact parking spaces that will fit in the lot will be:
N × 12.5 = 858
N = 858/12.5
N = 68
The non compact parking spaces that will fit in the lot will be:
N × 16.5 = 858
N = 858/16.5
N = 52
Learn more about area on:
brainly.com/question/7438648
#SPJ1
