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Mama L [17]
3 years ago
13

Is this statement true or false? Global warming may be a result of natural causes.

Physics
2 answers:
Xelga [282]3 years ago
5 0
I think it might be True
Vlad1618 [11]3 years ago
3 0
I believe the answer is:True
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One end of a horizontal spring with force constant 130.0 Ni'm is attached to a vertical wall. A 4.00-kg block sitting on the flo
tekilochka [14]

Answer:

Explanation:

When the spring is compressed by .80 m , restoring force by spring on block

= 130 x .80

= 104 N , acting away from wall

External force = 82 N , acting towards wall

Force of friction acting towards wall = μmg

= .4 x 4 x 9.8

= 15.68 N

Net force away from wall

= 104 -15.68 - 82

= 6.32 N

Acceleration

= 6.32 / 4

= 1.58 m / s²

It will be away from wall

Energy released by compressed spring = 1/2 k x²

= .5 x 130 x .8²

= 41.6 J

Energy lost in friction

= μmg x  .8

= .4 x 4 x 9.8 x .8

= 12.544 J

Energy available to block

= 41.6 - 12.544 J

= 29 J

Kinetic energy of block = 29

1/2 x 4 x v² = 29

v = 3.8 m / s

This will b speed of block as soon as spring relaxes. (x = 0 )

4 0
3 years ago
When the number of atoms on the right side a chemical equation matches the number of atoms on the left side of a chemical equati
Hitman42 [59]

Answer:

Balanced.

Explanation:

A Balanced Chemical equation is a scientific term that describes a chemical equation that has the same number of atoms on each side of the equation.

Hence, when the number of atoms on the right side of a chemical equation matches the number of atoms on the left side of a chemical equation, it is said to be BALANCED.

7 0
3 years ago
Can someone pls help with the last one
Leviafan [203]

Answer:

ummmmmmmmmmmm ask your teacher or perant for help

Explanation:

so umm ask an adult or teen figure and maybe you will get it write not sure do

6 0
3 years ago
You have a concave mirror of focal length 20 cm. You want to obtain a real image of double the
ExtremeBDS [4]

Between centre of curvature and principal focus.

6 0
3 years ago
An object is dropped from a height of 75.0 m above ground level. (a) determine the distance traveled during the first second.
barxatty [35]

The relevant formula we can use in this case would be:

h = v0 t + 0.5 g t^2

where,

h = height or distance travelled

v0 = initial velocity = 0 since it was dropped

t = time = 1 seconds

g = 9.8 m/s^2

 

So calculating for height h:

h = 0 + 0.5 * 9.8 m/s^2 * (1 s)^2

<span>h = 4.9 meters</span>

6 0
3 years ago
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