If a spring is stretched to twice the lengtj of its equilibrium position, by what factor does the energy stored in the spring ch
1 answer:
Answer:
the energy increases 4 times
Explanation:
A spring has an elastic potential energy that is given by the expression
K_e = ½ K (x-x₀)²
where x is the distance from the equilibrium point and k is the return constant
if the spring is stretched at x-x₀ = 2x₀, the energy value
K_e = ½ k (2x₀)²
K_e = ½ k 4 x₀²
K_e = 4 (½ k x₀²)
= 4
therefore the energy increases 4 times
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Answer:
(C). The line integral of the magnetic field around a closed loop
Explanation:
Faraday's law states that induced emf is directly proportional to the time rate of change of magnetic flux.
This can be written mathematically as;
is the rate of change of the magnetic flux through a surface bounded by the loop.
ΔФ = BA
where;
ΔФ is change in flux
B is the magnetic field
A is the area of the loop
Thus, according to Faraday's law of electric generators
∫BdL = = EMF
Therefore, the line integral of the magnetic field around a closed loop is equal to the negative of the rate of change of the magnetic flux through the area enclosed by the loop.
The correct option is "C"
(C). The line integral of the magnetic field around a closed loop