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olga_2 [115]
2 years ago
13

Proposed Exercise - Circular Movement

Physics
1 answer:
notka56 [123]2 years ago
5 0

Answer:

ωB = 300 rad/s

ωC = 600 rad/s

Explanation:

The linear velocity of the belt is the same at pulley A as it is at pulley D.

vA = vD

ωA rA = ωD rD

ωD = (rA / rD) ωA

Pulley B has the same angular velocity as pulley D.

ωB = ωD

The linear velocity of the belt is the same at pulley B as it is at pulley C.

vB = vC

ωB rB = ωC rC

ωC = (rB / rC) ωB

Given:

ω₀A = 40 rad/s

αA = 20 rad/s²

t = 3 s

Find: ωA

ω = αt + ω₀

ωA = (20 rad/s²) (3 s) + 40 rad/s

ωA = 100 rad/s

ωD = (rA / rD) ωA = (75 mm / 25 mm) (100 rad/s) = 300 rad/s

ωB = ωD = 300 rad/s

ωC = (rB / rC) ωB = (100 mm / 50 mm) (300 rad/s) = 600 rad/s

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Answer:

1. a

2. b

3. b

Explanation:

1.

Resistance is the property of a conductor to offer resistance to the flow of current. The lower the resistance better is  the conductivity of wire.

We know that the resistance of a wire depends on several factor which are inter-connected by an equation as:

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R = resistance of the wire

l = length of the wire

a= cross sectional area of the wire  

from the above relation we observe that

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R\propto \frac{1}{a}

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2.

As the collision between the electrons and protons increases the speed of the flow of charges will decrease because the opposite charges attract each other and as we know that electrical current is the rate of flow of charge.

3.

Heating up of wire due to sunlight will cause lattice vibration in the conductor and will obstruct the movement of the charges which build up electric current, hence increasing the resistance of conductivity.

7 0
2 years ago
What are the two kinds of nucleons?
Akimi4 [234]

Answer:

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Explanation:

5 0
3 years ago
Using Figure 2, what is the momentum of Train Car A before the collision?
Bess [88]

Answer:

Option A. 180000 Kgm/s.

Explanation:

From the question given above, the following data were obtained:

For Train Car A:

Mass of train car A = 45000 Kg

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Momentum of train car A =?

For Train Car B:

Mass of train car B = 45000 Kg

Velocity of train car B = 0 m/s

Momentum is simply defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, the momentum of train car A before collision can be obtained as follow:

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Momentum of train car A =?

Momentum = mass × velocity

Momentum = 45000 × 4

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5 0
2 years ago
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Answer:

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3 0
3 years ago
A sprinter with a mass of 70 kg accelerates at a rate of 5 m/
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F = ma

=   70kg ×  5ms⁻²

F =350N  

8 0
2 years ago
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