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3 years ago

What happens when an object has a density greater than that of the surrounding liquid?

Physics

2 answers:

Vadim26 [7]3 years ago

4 0

it sinks into the liquid

(e.g. water sinks under oil as it is more dense)

Schach [20]3 years ago

4 0

Answer: Thus, when an object has a density greater than that of the surrounding liquid then the object will sink into the liquid.

Explanation: Density is defined as mass per unit volume.

Mathematically, $Density= \frac{mass}{volume}$

This shows that density is proportional to mass of the object, that is, more is density more will be the mass of object.

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Stopping distance of vehicles When brakes are applied to a moving vehicle, the distance it travels before stopping is called sto

DochEvi [55]

Answer:

Stopping distance = 40m

Explanation:

Given the following :

Initial speed of vehicle before applying brakes = 72km/hr

Converting km/hr to m/s:

72km/hr = [(72 * 1000)m] / (60 * 60)

72km/hr = 72,000m / 3600s

72km/hr = 20m/s

Deceleration after applying brakes (-a) (negative acceleration) = - 5m/s^2

From the 3rd equation of motion:

v^2 = u^2 + 2as

Where v = final Velocity ; u= Initial Velocity ; a = acceleration and s = distance

Final velocity when the car stops will be 0

Therefore ;

v^2 = u^2 + 2as

0 = 20^2 + 2(-5)(s)

0 = 400 - 10s

10s = 400

s = 400/10

s = 40m

Therefore, the stopping distance of the car = 40 meters

7 0

3 years ago

Why do people have symptoms in their bodys

weeeeeb [17]

Body works like a computer whenever there is any problem it warns you and those warnings are termed as symptoms. Of the body doesn't show symptoms we won't be able to detect the problem in our body.

5 0

3 years ago

Read 2 more answers

Design a tension member and slip-critical splice to carry a factored load of 500 kips. Please use a wide-flange section for the

Svetlanka [38]

Answer:

Kindly check the explanation section.

Explanation:

For the design we are asked for in this question/problem there is the need for us to calculate or determine the strength in fracture and that of the yield. Also, we need to calculate for the block shear strength.

From the question, we have that the factored load = 500kips. Also, note that the tension splice must not slip.

Also, the shear force are resisted by friction, that is to say shear resistance = 1.13 × Tb × Ns.

Assuming our db = 3/4 inches, then the slip critical resistance to shear service load = 18ksi(refer to AISC manual for the table).

If db = 7/8 inches, then the shear force resistance for n bolt = 10.2kips, n > 49.6.

The yielding strength = 0.9 × Aj × Fhb= 736 kips > 500

The fracture strength = .75 × Ah × Fhb = 309 kips.

The bearing strength of 7/8 inches bolt at the edge hole and other holes = 46 kips and 102 kips.

4 0

4 years ago

Only one of three balls A, B, and C carries a net charge q. The balls are made from conducting material and are identical. One o

Zarrin [17]

Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

qA = ½ q

qB = ½ q

qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

qA = 1/2 (q / 2) = ¼ q

qC = ¼ q

qB = ½ q

At this point all spheres have a charge,

qA = ¼ q

qb = ½ q

qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

Q = ½ q + ¼ q = ¾ q

When splitting the charge

qB = ½ ¾ q = 3/8 q

qC = ½ ¾ q = 3/8 q

qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

Q = qA + QB + QC

Q = ½ q + 3/8 q + ¼ q

Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

8 0

3 years ago

A 480 g falcon reaches a speed of 75 m/s in a vertical dive. if we assume that the falcon speeds up under the influence of gravi

poizon [28]

Answer:

286.7 m

Explanation:

So we are assuming the PE of the falcon is converted to KE

KE = PE

1/2 (.480)(75)^2 = .480 (9.81)(h ) solve for h = 286.7 m

8 0

2 years ago