Answer:
You should use photomath, it would be more easier for u. Oh, and by the watñy Y=12
Answer:
The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)
<u>Solution:</u>
Given, equation is 
We have to find the vertex of the given equation.
When we observe the equation, it is a parabolic equation,
We know that, general form of a parabolic equation is
Where, h and k are x, y co ordinates of the vertex of the parabola.

By comparing the above equation with general form of the parabola, we can conclude that,
a = -6, h = 1 and k = 9
Hence, the vertex of the parabola is (1, 9).
Answer:
75 degrees
Step-by-step explanation:
Use trigonometry
we are given opposite(27) and hypotenuse(28), so use sin
sin=opp/hyp
sin(x)=27/28
x=arcsin(27/28)
x=74.64111442
I hope this helps you
-(4.2+1/2) ÷ (-)(2.3+2/3)
-9/2 ÷ - 8/3
9/2× 3/8
27/24
1 3/24