How do you graph a linear inequality in two variables

1 answer:

7 0

The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥. The half-plane that is a solution to the inequality is usually shaded.
Example:

Is (1, 2) a solution to the inequality
2x+3y>1
2times1+3times2>1
2+5>1
7>1

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Evaluate and reduce: 12 + (12) Enter the number that belongs in the green box. [?]

Firlakuza [10]

Answer:

Step-by-step explanation:

12 + (12)

first do for the bracket

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An author argued that more basketball players have birthdates in the months immediately following July 31, because that was the

Lady_Fox [76]

Answer:

There is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same frequency.

Step-by-step explanation:

In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same frequency.

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

H₀: The observed frequencies are same as the expected frequencies.

Hₐ: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

$\chi^{2}=\sum{\frac{(O-E)^{2}}{E}}$

The values are computed in the table.

The test statistic value is $\chi^{2}=128.12$ .

The degrees of freedom of the test is:

n - 1 = 12 - 1 = 11

Compute the p-value of the test as follows:

p-value < 0.00001

*Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same frequency.