Answer:
-4100
Step-by-step explanation:
Given x(x1,y1)=(2,4)
z(x2,y2)=(x2,y2)
midpoint (x,y)=(-1,1)
2+x2/2=-1;4+y2/2=1
2+x2=-2;4+y2=2
x2=-4;y2=-2
z(x2,y2)=(-4,-2)
Answer:
Yes.
Step-by-step explanation:
Given: f(x) = 2x^3 + x^2 - 5x + 2; x + 2
If x + 2 is a factor of f(x), then , by the Factor Theorem, f(-2) = 0.
So we check if this is so:
f(-2) = 2(-2)^3 + (-2)^2 - 5(-2) + 2
= -16 + 4 + 10 + 2
= -16 + 16 = 0.
So Yes x + 2 is a factor.
Answer:
A
Step-by-step explanation:
