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Pepsi [2]
3 years ago
10

Count by ones from 368 to 500. Change for a larger unit when necessary.

Mathematics
1 answer:
stepan [7]3 years ago
6 0
We can figure out how many numbers there are from 368 to 500 by subtracting.

500 - 368 = 132

Now, we need to get it in word form. This can be done by looking at the place value of each number.. So your answer would be:

1 hundred, 3 tens, and 2 ones.
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Answer choices: <br><br> 16/3<br> 40/9<br> 4/9<br> 4/3
son4ous [18]

Answer:

0.44444444 or 4/9

Step-by-step explanation:

Since we know the value of x, we can rewrite the equation replacing the variables.

\frac{2}{3}^{2} + 3*\frac{2}{3} - 2

Now solve. While solving, remember the order of operations.

\frac{2}{3}^{2} + 3*\frac{2}{3} - 2 = 0.44444444 or \frac{4}{9}

3 0
3 years ago
Kathy distributes jelly beans among her friends. Alia gets 4^2 fewer jelly beans than Kelly, who gets 3^3 jelly beans. How many
DochEvi [55]

"Alia gets 4^2 fewer than Kelly, who gets 3^3."

So it's about a subtraction.

\boxed{3^3-4^2}

Hope this helps.

r3t40

6 0
3 years ago
Read 2 more answers
The width of a rectangle is 7/15 of its length. The width of the rectangle is 56 cm. Find the length of the rectangle.
Hoochie [10]
W = 7/15 L

w = 56

56 = 7/15 L

56 x 15/7 = 7/15 x7 L

L = 120
8 0
3 years ago
37 - 6 * 4 + 32 / 8 working pls​
insens350 [35]

Answer:

17 is the answer

Step-by-step explanation

3 0
3 years ago
Read 2 more answers
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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