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3 years ago

Eight plus the quotient of a number and 3 is -2

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

8+(x\3)=-2 is the answer

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Find the area of this triangle.<br> 6 ft<br> 10 ft

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The area of this figure would be 30 ft^2 hope this helped!!

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2 years ago

Choose all properties that were used to simplify the following problem:

ycow [4]

All minus the addition

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3 years ago

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The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 60 o

Gala2k [10]

Answer:

Step-by-step explanation:

Given that the Acme Company manufactures widgets, which have a mean of 60 ounces and a standard deviation of 7 ounces

We know that 95% of the area lie between -2 and 2 std deviations from the mean.

i.e. Probability for lying in the middle of 95%

Z score $(60+7(-2), 60+7(2))\\=(46, 74)$

Between 46 and 74 oz.

b) Between 12 and 57

convert into Z score

$(\frac{12-60}{7}$

P(-6.86<z<-0.43)

=0.5-0.1664=0.3336

c) X<30 gives Z<-4.83

i.e. P(X<30) =0.00

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3 years ago

How much 3 1/4+9 3/8

antoniya [11.8K]

Answer:12 5/8

Step-by-step explanation:

Add the whole numbers together. 3 + 9 = 12

Multiply 1/4 so that it will have the same dnominator as 3/8. 2(1/4)= 2/8

Add the fractions together. 2/8 + 3/8 = 5/8.

Add the whole number and fraction to get a mixed number. 12 + 5/8 = 12 5/8

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3 years ago

Solve the system of equations using any method. 2X – Y + Z = – 2, 6X + 3Y – 4Z = 8, – 3X + 2Y +3Z = – 6

krok68 [10]

Answer:

Z = - 2, Y = 0, X = 0

Step-by-step explanation:

2X – Y + Z = – 2

6X + 3Y – 4Z = 8

– 3X + 2Y +3Z = – 6

isolate "X" in the first equation

2X - Y + Z = - 2 => isolate "2X"

2X = - 2 - Z + Y => divide either side by 2

X = - 1 - Z/2 + Y/2

substitute this value of X in the second two equations (applying the substitution method here)

6(- 1 - Z/2 + Y/2) + 3Y - 4Z = 8,

6Y - 7Z - 6 = 8

- 3(- 1 - Z/2 + Y/2) + 2Y +3Z = - 6,

Y + 9Z + 6/2 = - 6

isolate Y in the second equation (6Y - 7Z - 6 = 8) and substitute in the third equation (Y + 9Z + 6/2 = - 6)

6Y - 7Z - 6 = 8 => isolate 6Y

6Y = 14 + 7Z => divide either side by 6

Y = 7Z + 14/6 => substitute in second equation

7Z + 14/6 + 9Z + 6/2 = - 6 => solve for Z

61Z + 50/12 = - 6, Z = - 2

substitute the value of Z into the equations "Y = 7Z + 14/6" and using the value of Y and Z, substitute into "X = - 1 - Z/2 + Y/2"

Y = (7(- 2) + 14)/6 = 0 / 6

= 0

X = - 1 - (- 2)/2 + 0/2 = - 1 - (-1) + 0

= - 1 + 1 + 0 = 0

6 0

2 years ago