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FinnZ [79.3K]
3 years ago
13

What will you round 0.1365853

Mathematics
2 answers:
finlep [7]3 years ago
5 0
0.1365853 can be rounded to: 0.1 (Tenths), 0.14 (Hundredths), 0.137 (Thousandths), 0.1366 (Ten Thousandths)
Lapatulllka [165]3 years ago
5 0
Well I will round 0.1365853 to 0.14 or 0.1
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3) -5 + |-11| + -13<br><br> Step by step also
Advocard [28]

Answer:

-7

Step-by-step explanation:

-5+|-11|+-13

-5+11+-13

6+-13

= -7

3 0
3 years ago
Read 2 more answers
What is the slope of any line perpendicular to y=-1/3x+22
STatiana [176]
Answer:
The slope of any line perpendicular to the given line is 3

Explanation:
The general form of the linear line is:
y = mx + c where m is the slope
The given line is:
y = -1/3 x + 22
Comparing the given line with the general form, we will find that:
slope of the given line (m1) is -1/3

Now, for any two lines to be perpendicular, the product of their slopes should be equal to -1.
This means that:
m1 * m2 = -1
We have m1 = -1/3
Therefore:
-1/3 * m2 = -1
m2 = 3*1
m2 = 3

Hope this helps :)
5 0
3 years ago
The 16th term of an A.P. is 40 and the sum of the first 5 terms is 5. Find the sum of the first 50 terms.
KiRa [710]

Answer:

The sum of first 50 terms is 3425.

Step-by-step explanation:

Let the first tem of A.P be 'a' and it's common difference be 'd'

Thus the 16th term of the A.P is given by

T_n=a+(n-1)d\\\\40=a+15d..........(i)

Now we know that the sum of first 'n' terms of the A.P is given by

S_n=\frac{n}{2}[2a+(n-1)d]\\\\5=\frac{5}{2}[2a+4d]\\\\1=a+2d..........(ii)

Solving equation 'i' and 'ii' simultaneously we get

40=1-2d+15d\\\\13d=39\\\\\therefore d=3

Thus a=1-2\times 3=-5

Thus the sum of first 50 terms euals

S_{50}=\frac{50}{2}[2\times -5+(50-1)3]\\\\S_{50}=3425.

7 0
3 years ago
Read 2 more answers
Will mark brainly if correct please help
timama [110]
The answer is n=7 please mark Brainelist
3 0
2 years ago
Read 2 more answers
2. Solve by using the quadratic formula 3x2 - 6x - 4 = 0 round to the nearest hundredth.
lianna [129]

Answer:

let \:  \alpha  \: and \:  \beta  \: be \: two \: roots \: of \: above \:

equation \: .

\alpha  = 2.52 \: and \:  \beta  = -0.52

4 0
2 years ago
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