Given a circle having center A, and radius equal to AB.
One side of equilateral Triangle = AB
We have to draw two sides which have length equal to AB.
Draw a circle having center B and radius equal to AB.The Circle will pass through center A and cuts the Original circle at P.Join AP and BP.This is the equilateral triangle that we are interested in.
The Next in the construction of an equilateral triangle is:
Option B:→ Use a Compass to draw a circle centered at B with a radius that is equal to AB.
