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ArbitrLikvidat [17]

3 years ago

11

I KNOW IT'S LATE, BUT PLEASE HELP.

2 answers:

DedPeter [7]3 years ago

5 0

Answer: c. 30

Step-by-step explanation:

Given : Sam is building an enclosure with recycled cardboard for his collection of model cars.

So Sam's Design should be similar to Sam's project.

Since the similar shapes have the same side(Corresponding) ratio.

SideCD is corresponding to Side ML.

and SideAF is corresponding to Side JH.

Let SideAF be x.

Using values of JH= 5 in, ML = 6 in. and CD = 36 in , we have the following side ratio.

$\dfrac{x}{5}=\dfrac{36}{6}$

$\dfrac{x}{5}=6$

$x=6\times5=30$

Therefore the length of the side= 30 inches

Archy [21]3 years ago

4 0

7x6 bc its 7in in the desighn

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I need 27-32 and 33, 36, 39, 42 Thanks

MaRussiya [10]

27) Since it doesn't say which unit you're going to use, I'll say 3.5 inches.

28) 5.6 Ounces?

29) 375,000 Litres.

30) 120 Yards.

31) 355 ML.

32) 1,117KM.

I hope this much helped, the other questions my brain was too fried to do them, let me know if you need help with any of those though!

8 0

3 years ago

Solve for x if log 9 base x + log 3 base x^2 = 2.5

Y_Kistochka [10]

Not sure if the equation is

$\log_9x+\log_3(x^2)=\dfrac52$

or

$\log_x9+\log_{x^2}3=\dfrac52$

If it's the first one:

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}$

$9^{\log_9x+\log_3(x^2)}=x\cdot x^4$

$9^{\log_9x+\log_3(x^2)}=x^5$

On the other side of the equation, we'd get

$9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5$

Then

$x^5=3^5\implies\boxed{x=3}$

If it's the second one instead, you can use the same strategy as above:

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}$

(Note that this step assume $x>0$ )

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}$

$x^{\log_x9+\log_{x^2}3}=9\sqrt3$

Then we get

$9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}$

6 0

3 years ago

Consider the perfect square trinomial identity:

denis-greek [22]

Answer:

a = x

b = 5

Step-by-step explanation:

5 0

4 years ago

Use the given graph to determine the limit, if it exists.

ryzh [129]

Answer:

Maybe -3

Step-by-step explanation:

7 0

3 years ago

Can someone help me plss!!

kakasveta [241]

The answer is B mate

3 0

4 years ago

Read 2 more answers