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vfiekz [6]
3 years ago
9

A function has a domain of {1, 3, 5, 7} and a range of {2, 4, 6}. Which set of ordered pairs represents this function?

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0
For this case we have the following domain:
 {1, 3, 5, 7}
 We have the following range:
 {2, 4, 6}
 A value of the range belongs to each value of the domain.
 Therefore, the ordered pairs are:
 (1, 2)
 (3. 4)
 (5, 6)
 Answer:
 
A. {(1, 2), (3, 4), (5, 6), (7, 2)}
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Answer:

Exponential transformation.

Step-by-step explanation:

y = log_3 (x + 3) - 2

To transform this into exponential, we have:

Adding 2 to both sides

y + 2 = log_3 (x + 3)

3^(y + 2) = x + 3

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What equals 7 in multiplication
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Will there's 
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3 years ago
A software distributor charges \$41$41dollar sign, 41 per license of a particular utility. The distributor offers a 10\%10%10, p
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Answer:

1558

Step-by-step explanation:

The first 202020 licenses cost full price, which is \$41$41dollar sign, 41 each. Thus, the first 202020 licenses cost a total of \$41 \cdot 20 = \$820$41⋅20=$820dollar sign, 41, dot, 20, equals, dollar sign, 820.

Hint #2

The remaining licenses have a 10\%10%10, percent discount. That means they cost 90\%90%90, percent of the full price. Let's write 90\%90%90, percent in its decimal form, 0.90.90, point, 9, in order to multiply.

\qquad 0.9 \cdot \$41 = \$36.900.9⋅$41=$36.900, point, 9, dot, dollar sign, 41, equals, dollar sign, 36, point, 90

Hint #3

There are 40 - 20 = 2040−20=2040, minus, 20, equals, 20 licenses at the reduced price of \$36.90$36.90dollar sign, 36, point, 90. Thus, the remaining 202020 licenses cost a total of \$36.90 \cdot 20 = \$738$36.90⋅20=$738dollar sign, 36, point, 90, dot, 20, equals, dollar sign, 738.

Hint #4

To find the cost for all 404040 licenses, let's add the costs of the full price and discounted licenses.

\qquad \$820 + \$738 = \$1558$820+$738=$1558dollar sign, 820, plus, dollar sign, 738, equals, dollar sign, 1558

Hint #5

The business would pay \$1558$1558dollar sign, 1558 to buy the licenses.

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