Answer:
C. 905 in³
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, sphere
We know that the volume of a sphere is expresses as
V= 4/3πr³
Given that the diameter of the sphere is 12inches
Radius r= 12/2= 6 inches
Substituting our radius we can solve for the volume
V=4/3(3.142*6³)
V= (4*3.142*216)/3
V= 2714.68/3
V= 904.9in³
Approximately V= 905in³
Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
Good evening
Answer:
<h2>384</h2>
Step-by-step explanation:
s = 8 ⇒ 6s^2 = 6(8)²
= 6×64
= 384
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:)
Answer:
Step-by-step explanation:
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