at the zoo, there were 3 times as many monkey as lions. Tom counted a total of 24 monkey and linions. how many monkey were there

Sidana [21]

Answer:

A fraction is in simplest form if the top and bottom have no common factors other than 1. In other words, you cannot divide the top and bottom any further and have them still be whole numbers.

4 0

2 years ago

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A rectangular garden is to be fenced so that one of the sides is 5 feet longer than an adjacent side (s). Which of the following

Sophie [7]

The correct answer is: [B]: " s² + 5s " .
________________________________
A = s(s+5) = s² + 5s ;

→ which is: Answer choice: [B] .
________________________________

3 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Escribe una expresión algebraica para la palabra frase: el producto de 636 y un número w

diamong [38]

Answer:

636w

Step-by-step explanation:

producto = ×

$636 \times w\\\\= 636w$

5 0

2 years ago

andres has 4 bunches of balloons. there are 6 balloons in each bunchs how many balloons does andres have in all

Whitepunk [10]

$\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}$

1 bunch of balloons contain 6 balloons

$\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}$

Number of balloons in 4 bunches = ?

$\large\underline{\underline{\maltese{\purple{\pmb{\sf{\: Solution :-}}}}}}$

To find the number of balloons in 4 bunches we need to multiply the bumber of balloons in 1 bunch by the number of bunches.

$\tt\multimap \: number \: of \: balloons \: in \: 1 \: bunch \times number \: of \: bunches$

$\sf \nrightarrow \: 6 \times 4 = 24$

➪ Thus, There are 24 balloons in 4 bunches...~

8 0

2 years ago

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