at the zoo, there were 3 times as many monkey as lions. Tom counted a total of 24 monkey and linions. how many monkey were there

You score 64/75 on your first test. After your second test, your teacher tells you your test average is 88%

gregori [183]

First you need to divide 64 by 75 and then multiply by 100 which is 85.3% which then you need to find the average of the 2 which will be (85.3+x)/2=88 where x= the value of the second test.

Then you will need to isolate the x with the following steps:

multiply each side by 2 making it 85.3+x=176
Subtract 85.3 from each side
this results in 90.7

5 0

3 years ago

Read 2 more answers

Pls help me Find the correct answer

IrinaK [193]

I believe the answer would be D, 2y+6/9y-7 x 3/2 because dividing by a fraction is the same as multiplying by its reciprocal (the fraction flipped).
Hope I helped! ;)

6 0

3 years ago

Read 2 more answers

Discuss how the hot-hand theory relates to the accuracy of a professional basketball player. State whether you agree or disagree

m_a_m_a [10]

Talk about the hot hand theory relates to basketball state.

6 0

3 years ago

Please Hurry) Consider the quadratic equation 3x^2 - 6 = 2x. A) What is the value of the discrimination? B) What does the discri

Levart [38]

Answer:

A. 76

B. We will get two real solutions for the equation.

Step-by-step explanation:

A

For any quadratic equation ax²+bx+c=0, the discriminant is b²-4ac.

In 3x²-2x-6=0, a=3, b=-2 and c=-6:

b²-4ac

(-2)²-4(3)(-6)=4+72=76

B.

When the discriminate is positive we get two real solutions to the equation, when it's zero we get one real solution, and when it's negative we get two complex solutions. Since our discriminate, 76, is positive, we know that we will get two real solutions to 3x²-6=2x.

3 0

3 years ago

A university claims that the average cost of books per student, per semester is $300. A group of students believes that the actu

LenKa [72]

Answer:

$t=\frac{345-300}{\frac{200}{\sqrt{100}}}=2.25$

$p_v =P(t_{(99)}>2.25)=0.0133$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean is higher than 300 at 1% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=345$ represent the sample mean

$s=200$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =300$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 300, the system of hypothesis would be:

Null hypothesis: $\mu \leq 300$

Alternative hypothesis: $\mu > 300$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{345-300}{\frac{200}{\sqrt{100}}}=2.25$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=100-1=99$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(99)}>2.25)=0.0133$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean is higher than 300 at 1% of significance.

7 0

3 years ago