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3 years ago

Is 80 oz grater than 5 lb?

1 answer:

3 0

You need to convert lbs into ounces, so do 5×16, to get 80ounces and after doing jt, it woukd appear that 80 ounces and 5 lbs are equal to each other

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4. Which expression is equivalent to 3(x+6)?

lisov135 [29]

Answer:

Step-by-step explanation:

Cmon man, your not even trying.

3(x+6) is x+6+x+6+x+6 or 3x + 3(6).

That simplified is 3x + 18

6 0

4 years ago

How to get the answer.

Anna007 [38]

9514 1404 393

Answer:

1.05 × 1.05 × 1.05 × 1.05 × 1.05 = 1.2762815625

Step-by-step explanation:

An exponent indicates how many times the base is a factor in the product. That is, 1.05 to the 5th power means ...

1.05⁵ = 1.05 × 1.05 × 1.05 × 1.05 × 1.05

This multiplication expression is evaluated in the usual way.

= 1.1025 × 1.05 × 1.05 × 1.05

= 1.157625 × 1.05 × 1.05

= 1.21550625 × 1.05

= 1.2762815625

All scientific and graphing calculators have a button for computing the power of a number. On my calculator its label is $\displaystyle \boxed{y^x}$ . The particulars of the function of this button can be found in the manual for your calculator.

For on-line calculators, such as the go.ogle calculator, or the Desmos graphing calculator, the caret (^) is used to signify an exponent. (See the input line in the first attachment for an example.)

6 0

3 years ago

What is the greatest common factor of 90 and 135?

RSB [31]

Answer:

GCF = 45

Step-by-step explanation:

90 = 9×10 = 3²×2×5

135 = 45×3 = 9×5×3 = 3²×5×3 = 3³×5

GCF = 3²×5 = 9×5 = 45

6 0

3 years ago

How does one integrate the following:

grin007 [14]

Consider substituting $u=4+xy$ , so that $\mathrm du=x\,\mathrm dy$ . Then

$\displaystyle\int_{x=a}^{x=b}\int_{y=a}^{y=b}\frac x{(4+xy)^2}\,\mathrm dy\,\mathrm dx=\int_{x=a}^{x=b}\int_{u=4+ax}^{u=4+bx}\frac1{u^2}\,\mathrm du\,\mathrm dx$
$=\displaystyle\int_{x=a}^{x=b}\left(-\frac1u\right)\bigg|_{u=4+ax}^{u=4+bx}\,\mathrm dx$
$=\displaystyle\int_{x=a}^{x=b}\left(\frac1{4+ax}-\frac1{4+bx}\right)\,\mathrm dx$

Then by similar substitutions, you can easily find that you end up with

$\dfrac1a\ln|4+ax|-\dfrac1b\ln|4+bx|\bigg|_{x=a}^{x=b}$
$=\dfrac1a\ln|4+ab|-\dfrac1b\ln|4+b^2|-\dfrac1a\ln|4+a^2|+\dfrac1b\ln|4+ab|$
$=\dfrac1a\ln\left|\dfrac{4+ab}{4+a^2}\right|+\dfrac1b\ln\left|\dfrac{4+ab}{4+b^2}\right|$

Of course, this all assumes that the integrand is continuous over the domain of integration, which would require that $a,b$ are chosen such that $xy\neq-4$ for any $(x,y)\in[a,b]^2$ . If in particular $ab>-4$ , then we can write

$=\dfrac1a\ln\dfrac{4+ab}{4+a^2}+\dfrac1b\ln\dfrac{4+ab}{4+b^2}$

and you can combine the logarithms if you like as

$=\ln\sqrt[a]{\dfrac{4+ab}{4+a^2}}+\ln\sqrt[b]{\dfrac{4+ab}{4+b^2}}$
$=\ln\left(\sqrt[a]{\dfrac{4+ab}{4+a^2}}\sqrt[b]{\dfrac{4+ab}{4+b^2}}\right)$

7 0

3 years ago

Ax - 8 = x + 2 If x = 2 on the equation above, what is the value of a?

aev [14]

Answer:

a=2

Step-by-step explanation:

ax-8=x+2

when x=2

2a-8=2+2

2a=4+8

2a=12

a=12/2=6

6 0

4 years ago

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