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vodka [1.7K]
3 years ago
8

A movie was shown 6 times every day from November 24 through December 19. How many times was the movie shown in all? (Note: The

month of November has 30 days.)
Mathematics
2 answers:
katen-ka-za [31]3 years ago
4 0

Answer:

Answer: A. 138 times

How?

During that time period there were 23 days so 23 multiplied by the amount of times played per day (6)

You get the answer 138

Step-by-step explanation:

nignag [31]3 years ago
4 0

Answer:

156 times

Step-by-step explanation:

Given: A movie was shown 6 times every day from November 24 through December 19.

To find: The number of times the movie shown in all.

Solution:

To find the number of times the movie shown in all, we need to first find the number of days the movie is shown.

So, we have to find the number of days from November 24 through December 19.

Number of days the movie is shown in November is 7 days.

In December the movie is shown for 19 days.

So, we get the movie is shown for 26 days in all.

It is given that, each day the movie is shown 6 times.

So, to find the total number of times the movie is shown we need to multiply 26 and 6.

Therefore, we get

number of times movie shown=26\times6=156

Hence, the movie is shown 156 times.

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Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each
emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2

Jake wants to increase the area by 50%, so the new area would be:

A'=168(1.5) \\ \\ A'=252ft^2

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

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