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olasank [31]
3 years ago
11

Can someone help me please? (Math)

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
Let   y = \frac{x}{2}  +  3   be line₁
And the perpendicular angle be line₂


If a line is perpendicular to another, then the product of their gradients is -1, which means that the gradient of line₂ would be the negative reciprocal of line₁

Based on that, if the gradient of line₁ is \frac{1}{2}
                   then, the gradient of line₂ is - 2.

Now by using the point-slope form  y - y₁ = m ( x - x₁)

If line₂ passes through the line (1,8) and have gradient -2,
then by exploiting the point-slope form  y - 8 = -2 (x - 1)

∴ equation of the ine perpendicular to y = \frac{x}{2}  +  3   would  be y = -2x + 10

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Please answer correctly !!!!! Will mark brainliest !!!!!!!!!!!
vesna_86 [32]

Answer:

your answers are already  matched up

Step-by-step explanation:

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3 years ago
A paper container in the shape of a right circular cone has a radius of 3 inches and a height of 8 inches. Determine and state t
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Given:

Radius of the cone = 3 inches

Height of the cone = 8 inches

To find:

The volume of the cone, in terms of  π.​

Solution:

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V=\dfrac{1}{3}\pi (3)^2(8)

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7 0
2 years ago
Please help! I'll give brainliest to whom is correct!
olga2289 [7]

Answer:

I THINK IT IS THE LAST ONE

Step-by-step explanation:

8 0
2 years ago
6 m
dimulka [17.4K]

Answer:

51.63m^3

Step-by-step explanation:

The figure is made up of a rectangle, triangle and a semi circle

Area of the figure = Area of triangle + rectangle + semicircle

Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2 * 3 * 5

Area of the triangle = 15/2

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Area of the rectangle = 30m^2

Area of the semicircle = πr²/2

Area of the semicircle = π(3)²/2

Area of the semicircle = 3.14(9)/2

Area of the semicircle = 3.14 * 4.5

Area of the semicircle = 14.13m^2

The area = 30 + 14.13+7.5

Area of the figure = 51.63m^3

7 0
3 years ago
Read 2 more answers
The measure of a side of a square is x units. A new square is formed with each side 6 units longer than the original squares sid
xenn [34]
We know that
[area old square]=x*x--------> x²

[area new square]=(x+6)*(x+6)-------> (x+6)²-----> A=x²+12x+36

the answer is  
An <span>expression to represent the area of the new square is (</span>x²+12x+36)
4 0
3 years ago
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