Answer:
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 590 hours.
This means that 
Find the probability of a bulb lasting for at most 605 hours.
This is the pvalue of Z when X = 605. So



has a pvalue of 0.8413
0.8413 = 84.13% probability of a bulb lasting for at most 605 hours.
The exponential equation that can model the value of the camper van , in x years is y = 38000*(0.85)ˣ .
In the question ,
it is given that
the present value of the camper van (P₀) = $38000
given the depreciation rate is 15% each year (r)= -0.15
The future value y ,of the camper van can be given by the formula
y = P₀*(1 + r)ˣ
On putting the values , we get
y = 38000*( 1 - 0.15)ˣ
y = 38000*(0.85)ˣ
Therefore , The exponential equation that can model the value of the camper van , in x years is y = 38000*(0.85)ˣ .
Learn more about Exponential Equation here
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Answer:
y = 3/-4x + 2
Step-by-step explanation:
Answer:
67%
Step-by-step explanation:
There are a few methods to finding the percent of a number. You can use proportions:

The 'percent' is the percent of the fraction that you are looking for, or 48/72.
Cross-multiply: 72x = (48)(100) or 72x = 4800
Divide both sides by 72: 72x/72 = 4800/72
Solve for 'x': x = 66.6666...
Round 66.666.... to the nearest percent: 67%
Answer:
its not working so i cant :(
Step-by-step explanation: