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Gelneren [198K]
3 years ago
8

Which of the following will affect the rate of a chemical reaction?

Chemistry
2 answers:
dimulka [17.4K]3 years ago
7 0

Answer:

Solute concentration will afect the rate of a chemical reaction, because you must work with molarity

Explanation:

I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.

If you want to know more, you have to consider temperature in the reaction and the  presence of catalysts. They all, affect reactions.

s344n2d4d5 [400]3 years ago
7 0

Answer:

Solute Concentration

Explanation:

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Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo
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The relative volumes of chloroform and water that should be used is 9:10

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Concentration of solution in water = 10 ( moles of water )

Dissociation constant at 25^oC; K_D = 10

K_D = Concentration of solution in chloroform / Concentration of solution in water

Meaning;

K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }

Since 90 mole is present in chloroform and 10 mole is present in water, Total mole of Caffeine present is 100

Now, we substitute our given values into the equation

10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}  \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10

Therefore, the relative volumes of chloroform and water that should be used is 9:10

Learn more; brainly.com/question/11060225

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Classify the following aqueous solutions as: strong acid, weak acid, neutral, weak base, or strong base.
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Find the mass of 3.00 mol of acetic acid, C2H4O2.
Alexeev081 [22]
Molar mass 

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m = 3.00 * 60.0

m = 180 g of <span>C₂H₄O₂ 

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Example:

Ionic Compounds. A metal with a non-metal. Doesn't use prefixes for naming. Name the metal and change the nonmetal ending to -ide.

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