Answer:
-205.7kj
Explanation:
Now adding reaction 2 and twice of reaction 3 and reverse of reaction 1, we get the enthalpy of the reaction.
The expression for enthalpy for the following reaction will be,
where,
n = number of moles
Now put all the given values in the above expression, we get:
Therefore, the enthalpy of the following reaction is, -205.7kj
Answer:
- False.
- False.
- True.
- True.
Explanation:
Hello, for each statement we state:
- An exponent of "2" means that if we double the concentration of the reactant the rate doubles as well.
FALSE because considering a rate law like:
The exponent of "2" powers the concentration to the second power, not doubles the rate law, thus, if C is 3, for k=1, r will be -9. On the other hand if the rate is like:
The rate will be -3, that is why the rate is not doubled when the "2" in concentration is present.
- Exponents in rate laws are based on the coefficients from the balanced equation.
FALSE because for nonelemental chemical reactions, the exponents do not match with each species' stoichiometric coefficients in the rate law.
- The rate constant, k, takes into account the effect of activation energy and temperature on the reaction.
TRUE, since the Arrhenius equation allows us to prove the effect of the activation energy and the temperature:
- Differential rate laws allow us to compare concentration and time.
TRUE as they are given like:
Best regards.