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goblinko [34]
3 years ago
7

What mass of oxygen forms from 71.89 g CO2? Use the periodic table to find molar masses.

Chemistry
1 answer:
Paraphin [41]3 years ago
8 0
Atomic mass C = 12.0107
Atomic mass O= 15.9994
Calculate the molecular mass of the CO2
12.0107 + (2 x 15.9994) = 44.0095

Multiply the mass of CO2 by the conversion factor that relate the O mass to the molecular mass of CO2 to find the mass of O in the 71.89g of CO2

71.89 g CO2 x (2 x 15.9994) / 44.0095 =

52.2703900748702

52.27 g O

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What is the formula of the ion formed when tin achieves a stable electron configuration?
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1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

8 0
2 years ago
Will mark as Brainliest.
stealth61 [152]
The answer you are looking for is A. If you need me to show you how I got the answer let me know. :)
3 0
3 years ago
Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12




3 0
3 years ago
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