The analysis of a compound gives the following percent composition by mass: C: 52.14 percent; H: 9.946 percent; S: 12.66 percent
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<u>Answer:</u> The mass of produced is 2.52 g
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
- <u>For hexane:</u>
Given mass of hexane = 1.72 g
Molar mass of hexane = 86.18 g/mol
Putting values in equation 1, we get:
- <u>For oxygen gas:</u>
Given mass of oxygen gas = 8.0 g
Molar mass of oxygen gas= 32 g/mol
Putting values in equation 1, we get:
The chemical equation for the combustion of hexane follows:
By stoichiometry of the reaction:
If 2 moles of hexane reacts with 19 moles of oxygen gas
So, 0.020 moles of hexane will react with = of oxygen gas
As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Thus, hexane is considered a limiting reagent because it limits the formation of the product.
By the stoichiometry of the reaction:
If 2 moles of hexane produces 14 moles of
So, 0.020 moles of hexane will produce = of
We know, molar mass of = 18 g/mol
Putting values in above equation, we get:
Hence, the mass of produced is 2.52 g