<u> 70</u> =<u>63</u><u>
</u>100 ?
cross multiply 63 and 100= 6300 then divide by 70= 90
Answer:
Step-by-step explanation:
eq. of circle with center (h,k) and radius=r is
(x-h)²+(y-k)²=r²
reqd. eq. is
(x-2)²+(y+5)²=9²
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
302
Step-by-step explanation: