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jonny [76]
2 years ago
7

Evaluate each of the following values for the f(x)= [x] (a) -2.3 (b) 0.7 (c)1.4 (d) 3.6 (e)10.8

Mathematics
1 answer:
Ivenika [448]2 years ago
7 0
Question b
Answer: ⇒ 0.7 = 0.7

Question c
ANSWER:⇒ 1.4 = 1.4

Question d
ANSWER:⇒ 3.6 = 3.6

Question e
ANSWER:⇒ 10.8 = 10.8
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Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99

And now we can solve for \lambda

0.01 \geq e^{-\lambda}(1+\lambda)

Applying natural log on both sides we have:

ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)

ln(0.01) \geq -\lambda+ln(1+\lambda)

\lambda-ln(1+\lambda)+ln(0.01) \geq 0

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

4 0
3 years ago
Convert 60 miles per hour into meters per second
Svetllana [295]
1,609.35 meters are in a mile.
3,600 seconds are in an hour.

1,609.35meters x 60miles = 96,561 meters per hour
96,561meters per hour / 3,600seconds = 26.82 meters per second
3 0
3 years ago
How to turn 1.15 as a decimal into a percentage
Valentin [98]
Multiply the number by 100, making this one 115%
6 0
3 years ago
Chord AC intersects chord BD at point P in circle Z.
Alik [6]

In this question, we have to use the intersecting chord theorem, and the formula which is

AP * CP = BP * DP

In the given circle, values of AP, CP and DP are 12m, 6m and 5m respectively .

Substituting the values in the formula, we will get

12*6 = 5BP

Dividing both sides by 5

BP = \frac{72}{5} = 14.4 m

4 0
3 years ago
Read 2 more answers
Which shows how the distributive property can be used to evaluate 7 times 8 and four-fifths?
IrinaK [193]

Answer:

I have no clue as to what the options were, but the answer is 61 and three-fifths.

Step-by-step explanation:

<em>Well, the fraction options were a little distorted, so I'll work it out anyway.</em>

<em />

7 • 8 4/5

7(8 + 4/5)

<em>7 • 8 is 56, and 7 • 4/5 is 28/5.</em>

56 + 28/5

<em>28/5 as a mixed-number fraction (I think that's what it's called) is 5 3/5.</em>

56 + 5 + 3/5

61 + 3/5

61 3/5 (61 and three-fifths)

There!

<em>(Sorry about not getting the options...)</em>

6 0
3 years ago
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