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iren2701 [21]
3 years ago
7

Milk & Cookies is an ice cream sandwich stand.

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
5 0

Answer:-1

Step-by-step explanation:

2 dollars gained in July 2 dollars gained in August and 5 dollars lost in September is -1

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At a hardware store, each wooden plank costs $3.57. How much do 12 planks cost?
777dan777 [17]
To find this answer, we need to multiply 3.57 by 12.
3.57 * 12 = 42.84
Therefore, 12 planks will cost $42.84.
5 0
3 years ago
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SIMPLE HELP HELP HELP PLEASE ONLY 1 ANSWER NONE OF THE ABOVE OR ALL IS NOT THE ANSWER SO PLEASE DO IT RIGHT THIS TIME WILL GIVE
Eva8 [605]

Answer:

A

The first option is the correct!

They are parallel so they never connect! :)

Photos attached!

Hope this helps! Have a great day! :)

7 0
3 years ago
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Si elegimos un día de la semana al azar, ¿qué probabilidad hay de que sea fin de semana (ya sabemos que hay dos días…)?
irga5000 [103]

Answer:

La probabilidad que hay de que sea fin de semana es \frac{2}{7}

Step-by-step explanation:

La Probabilidad es la mayor o menor posibilidad de que ocurra un determinado suceso. En otras palabras, la probabilidad establece una relación entre el número de sucesos favorables y el número total de sucesos posibles. Entonces, la probabilidad de un suceso cualquiera A se define como el cociente entre el número de casos favorables (número de casos en los que puede ocurrir o no el suceso A) y el número total de casos posibles. Esta se denomina Ley de Laplace.

P(A)=\frac{numero de casos favorables}{numero de casos posibles}

En este caso:

  • número de casos favorables: 2 (cantidad de días del fin de semana)
  • número de casos posibles: 7 (cantidad de días totales en la semana)

Reemplazando:

P(A)= \frac{2}{7}

<u><em>La probabilidad que hay de que sea fin de semana es </em></u>\frac{2}{7}<u><em></em></u>

3 0
3 years ago
in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok
grandymaker [24]

Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

6 0
3 years ago
Free cheat!!!!division!!
swat32

Answer:

thats helpful

Step-by-step explanation:

6 0
3 years ago
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