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Luden [163]
3 years ago
12

Answer the question in the pic :)

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0
3 is D I’m not sure ab 4
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Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil
andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that p = 0.26

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that n = 5

4 failures, so 1 success, and we have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898

0.3898 = 38.98% probability that there will be 4 failures

4 0
3 years ago
PLEASE HELP ALGEBRA 2
svet-max [94.6K]


1) I use an interest program on my calculator. You could also use the equation listed in the math textbook. Principle=2500  Rate=0.025   Years=3 No.compounds/yr=4   Answer is $2,694.08

2) All positives

3) Square root of 343

4) Square root of 48

I hope that helps. :)

4 0
3 years ago
What is one reason why we add and subtract decimals
NemiM [27]
Because if you did not you would not have a exact answer.

5 0
3 years ago
Read 2 more answers
Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations
marusya05 [52]

Answer:

Sin \angle A =0.80

Cos \angle A=0.60

Sin \angle B =0.60

Cos \angle B=0.80

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle A =\frac{BC}{BA}

Substitute values for BC and BA

Sin \angle A =\frac{8cm}{10cm}

Sin \angle A =\frac{8}{10}

Sin \angle A =0.80

Cos \angle A=\frac{AC}{BA}

Substitute values for AC and BA

Cos \angle A=\frac{6cm}{10cm}

Cos \angle A=\frac{6}{10}

Cos \angle A=0.60

Solving (b): Sine and Cosine B

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle B =\frac{AC}{BA}

Substitute values for AC and BA

Sin \angle B =\frac{6cm}{10cm}

Sin \angle B =\frac{6}{10}

Sin \angle B =0.60

Cos \angle B=\frac{BC}{BA}

Substitute values for BC and BA

Cos \angle B=\frac{8cm}{10cm}

Cos \angle B=\frac{8}{10}

Cos \angle B=0.80

Using a calculator:

A = 53^{\circ}

So:

Sin(53^{\circ}) =0.7986

Sin(53^{\circ}) =0.80 -- approximated

Cos(53^{\circ}) = 0.6018

Cos(53^{\circ}) = 0.60 -- approximated

B = 37^{\circ}

So:

Sin(37^{\circ}) = 0.6018

Sin(37^{\circ}) = 0.60 --- approximated

Cos(37^{\circ}) = 0.7986

Cos(37^{\circ}) = 0.80 --- approximated

8 0
3 years ago
Read 2 more answers
Solve the equations<br>Y=2x-4, 3x+y=1​
liberstina [14]

Step-by-step explanation:

y = 2x - 4

3x + y = 1

y = 1 - 3x

Equating,

2x - 4 = 1 - 3x

2x + 3x =  1 + 4

5x = 5

x = 1

Placing it,

y = 1 - 3(  1)

y = 1 - 3

y =  - 2

6 0
3 years ago
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