<img src="https://tex.z-dn.net/?f=%28y%20-%201%29%20%5E%7B2%7D%20" id="TexFormula1" title="(y - 1) ^{2} " alt="(y

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My name is Ann [436]

3 years ago

ign="absmiddle" class="latex-formula">

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

7 0

(a-b)^2=a^2-2ab+b^2

this translates to

y^2-2y+1

Hope this helps!

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Twenty-five teenagers were surveyed about food. Five more preferred pizza than steak. Write and solve system of equations to fin

viktelen [127]

Hope this helps! I can resubmit if my hand writing is too bad.

6 0

4 years ago

Farmer Bill sold potatoes at the farm market. He sold a quarter to the first person, 4/9 of what was left to the second person,

mel-nik [20]

Answer: 120 lb of potatoes.

Step-by-step explanation:

Let the pounds of potatoes sold by farmer Bill = X lb

Fractional part sold to the first person = 1/4

Therefore 1/4 of X = 1/4 x X

= X/4 lb of potatoes.

No of potatoes left for sale = X - X/4

= ( 4x - x )/4

= 3x/4 lb.

Fractional part sold to the second person out of the reminder = 4/9

Therefore 4/9 of 3x/4 = 4/9 x 3x/4

= x/3 lb of potatoes.

Amount of potatoes left for sale = 3x/4 - x/3

Resolve into fraction , we have = (9x - 4x)/12, because 12 is the LCM.

= 5x/12

Third buyer bought 4/5 of the left over = 4/5 of 5x/12

= x/3 lb of potatoes.

Amount of potatoes left = 5x/12 - x/3

Resolve in to fraction again taking 12 as the LCM = ( 5x - 4x )/12

= x/12 lb of potatoes .

Therefore, the left over was 10 lb .

To determine the value of x now which correspond to the amount of potatoes sold by Farmer Bill, we shall the equate the left to x/12 = 10

we now cross multiply to get the value of x x = 120 lb.

therefore the pound of potatoes sold by farmer Bill = 120 lb.

4 0

3 years ago

3(x+4) - 5(x - 1) < 5

DaniilM [7]

Answer:

It's E. x > 6

Step-by-step explanation:

8 0

3 years ago

Find the value of the variable if P is between J & K.

Mama L [17]

Answer:

Step-by-step explanation:

well you see I just guessed :D

5 0

4 years ago

Find the equation of the tangent line to the curve 2exy=x+y at (0,2).

DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

Step(i):-

Given function = f(x,y) = $2e^{xy} -x-y=0$ ...(i)

Differentiating equation (i) with respective to 'x' , we get

$2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0$

apply formula

$\frac{d}{dx} (UV) = UV^{l} +V U^{l}$

step(ii):-

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0$

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0$

Taking common d y/d x

$(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))$

$\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}$

put At (0,2)

$\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3$

slope of the curve m = 3

Step(iii):-

The equation of the tangent line to the curve

$y-y_{1} =m(x-x_{1} )$

y - 2 = 3 ( x - 0 )

3 x - y = 2

Final answer:-

The equation of the tangent line to the curve

3 x - y = 2

8 0

3 years ago