Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
y = -5/3x + 4/3z
Step-by-step explanation:
5x + 3y = 4z
3y = -5x + 4z
y = -5/3x + 4/3z
Answer:
B.
Step-by-step explanation:
5$ ticket per ride = 5x
y = 5x
table A
Graph B
Answer:
i realy dont known dude haaaaaaaahaaahahahah
Step-by-step explanation:
It would be 7x3 which would equal 21. Hope that helped!