Question

What are the zeros of the function f(x)=x^2+x-20?

Answer 1

The zeros are x = - 5 and x = 4

x² + x - 20 = 0
(x + 5)(x - 4) = 0

Set each binomial equal to zero.

x = - 5, 4

Answer 2

Answer:

The zeroes of the given function are -5 and 4.

Step-by-step explanation:

The given function is

$f(x)=x^2+x-20$

Equate the given function equal to 0, to find the zeroes of the given function.

$x^2+x-20=0$

Write the middle term as 5x-4x.

$x^2+5x-4x-20=0$

$(x^2+5x)+(-4x-20)=0$

Taking out common factors from each parenthesis.

$x(x+5)-4(x+5)=0$

$(x-4)(x+5)=0$

Using zero product property, we get

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore the zeroes of the given function are -5 and 4.