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barxatty [35]
3 years ago
15

What is the second term in the binomial expansion of (2r-3s)12?

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

Its A.

Step-by-step explanation:

Reptile [31]3 years ago
5 0
(a+b)^n=\displaystyle\sum_{k=0}^n\binom nka^{n-k}b^k

where \dbinom nk=\dfrac{n!}{k!(n-k)!}. The second term of the expansion occurs when k=1.

So the second term of the expansion of (2r-3s)^{12} is

\dbinom{12}1(2r)^{12-1}(-3s)^1=12(2r)^{11}(-3s)=-73728r^{11}s
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