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barxatty [35]
3 years ago
15

What is the second term in the binomial expansion of (2r-3s)12?

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

Its A.

Step-by-step explanation:

Reptile [31]3 years ago
5 0
(a+b)^n=\displaystyle\sum_{k=0}^n\binom nka^{n-k}b^k

where \dbinom nk=\dfrac{n!}{k!(n-k)!}. The second term of the expansion occurs when k=1.

So the second term of the expansion of (2r-3s)^{12} is

\dbinom{12}1(2r)^{12-1}(-3s)^1=12(2r)^{11}(-3s)=-73728r^{11}s
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7/80

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Where P(B) is the probability of event B occurring, P(A ∩ B) is the probability of event A and event B occurring and P(A|B) is the probability of event A occurring given event B.

P(A|B)=\frac{P(A \cap B)}{P(B)}\\\\P(A \cap B)=P(A|B)*P(B)\\\\Substituting:\\\\P(A \cap B)=1/4*7/20=7/80\\\\P(A \cap B)=7/80

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