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goblinko [34]
3 years ago
6

List least to greatest

Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

C, 3 1/2, 3 19/20, 3 39/40

Step-by-step explanation:

to make this a bit easier, we can put the mixed numbers into improper fractions:

3 39/40 becomes 159/40

3 19/20 becomes 79/20

3 1/2 becomes 7/2

comparing them to each other, we see they have unlike denominators. we need to get the denominators alike so we can compare them easier

the fractions all have a common denominator of 40, so we need to multiply each fraction by a number that gives us a denominator of 40

159/40 is already fine

79/20 needs to be multiplied by 2 to get a denominator of 40

79/20 x 2 = 158/40

7/2 needs to be multiplied by 20 to get a denominator of 40

7/2 x 20 = 140/40

from least to greatest, we have the following:

140/40, 158/40, 159/40

in their original form this would be:

3 1/2, 3 19/20, 3 39/40

the answer would be C

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Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins
Zanzabum

The expression Hallie wrote is not clear, because if 0 is the only number that satisfies p = 4l + 4w + 4h = l + w + h.

But if you meant to write:

p = 4l + 4w + 4h

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then she could get something different.

Answer:

The expression (w + h) + p/4 should follow the subtraction if Hallie's equation is

p = 4l + 4w + 4h

p/4 = l + w + h

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Step-by-step explanation:

Let us solve Hallie's problem.

She can use the equation:

p = 4l + 4w + 4h

to determine the sum of the lengths of the edges of a rectangular prism. Because she begin to solve the equation for h, let us solve for h.

This means we are trying to make h the subject of the formula.

p = 4l + 4w + 4h

When you factor out 4 on the right hand side, you have

p = 4(l + w + h)

Dividing both side by 4, we have

p/4 = l + w + h

Now, subtracting (l + w) from both sides, we have

p/4 - (l + w) = h.

This can be written as:

h = - (l + w) + p/4

And that is what Hallie wanted to obtain.

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Im stuck on this question helm me out I will mark you as brainliest​
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Answer: <em><u>it is =4176000000000000</u></em>

Step-by-step explanation:

(2.9)(100000)(7.2)(10^2)

5(10^−8)

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(290000)(7.2)(10^2)

5(10^−8)

=

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5(10^−8)

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5(10^−8)

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8 0
3 years ago
Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at
Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation  that models the height of the gum in centimeters above the ground at any time, t, in seconds.  can be written as:

\mathbf {y = 34cos (\pi (t-1.25))+34}

where;

y =  is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

\mathbf{ \pi} = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m  to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

\mathbf {y = 34cos (\pi (15.6-1.25))+34}

\mathbf {y = 34cos (\pi (14.35))+34}

\mathbf {y = 34cos (45.08)+34}

\mathbf{y = 58.01}

Thus, the  gum is at 58.01 cm from the ground at  t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

\mathbf {y = 34 cos(\pi (t-1.25))+34}

\mathbf{12 = 34 cos ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = cos (\pi(t-1.25))

\dfrac {-22}{34} = cos(\pi(t-1.25))

2.27 = (\pi (t-1.25)

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

\mathbf {y = 34 sin (\pi (t-1.25))+34}

\mathbf{12 = 34 sin ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = sin (\pi(t-1.25))

\dfrac {-22}{34} = sin (\pi(t-1.25))

-0.703 = (\pi(t-1.25))

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0
3 years ago
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