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solniwko [45]
3 years ago
15

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

I would say two cupsssssss

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A ball thrown in the air vertically from ground level with initial velocity 37 m/s has height h(t) = 37t − 4.9t2 m at time t (in
Nesterboy [21]

Answer:

46.57

Step-by-step explanation:

Given that:

h(t) = 37t - 4.9t²

When the ball reaches the ground, then the height is zero;

So, we equate h(t) to zero and solve for t

37t - 4.9t² = 0

t = 0, 7.55

Let the Initial time be  a = t = 0

The time the ball reaches the ground be b = 7.55

So, the average height can now be calculated as:

Average height = \frac{1}{b-a}\int\limits^b_a {h(t)} \, dt

= \frac{1}{7.55-0}\int\limits^{7.55}_0 (37t-4.9^2)   dt

= \frac{1}{7.55-0}\ (\frac{37(7.55)^2}{2} - \frac {4.9(7.55)^3}{3})

= \frac{1}{7.55-0}\ (351.6104208)

= 46.57091665

≅ 46.57  to (2 decimal places)

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3 years ago
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murzikaleks [220]

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C. both A and B

Step-by-step explanation:

The student incorrectly applied the Distributive Property in Step 1 by not multiplying 8 and 7. Then they added 7 to 7 to cancel them out, but subtracted 7 from 75 instead of adding like they did on the other side of the equal sign.

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Step-by-step explanation:

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