Answer: a) 46 minutes
b) 10:47
The basic knowledge for this is that 60 minutes = 1 hour
<u>a)</u> Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes
Here you go! Total 46 minutes from Mosley to Bamford.
<u>b)</u> From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.
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Your answer would be -35.
The function given can be classified as a function. That is option C.
<h3>What is a function in mathematics?</h3>
Function can be defined as the expression that has both an x domain value and a y range value and it's being classified based on the quality of these values.
A function can be represented based on their roster forms.
Using the function equation given, f(X) = 10.2^2
Here, the first element is the domain or the x value and the second element is the range or the f(x) value of the function.
Learn more about arithmetic function here:
brainly.com/question/10439235
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Answer:
The SA of the rectangle is 270. The SA of both the triangles is 24
Answer:
a) 
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that A and B are independent events
P(A∩B) =P(A) P(B)
we will use the conditional probability
or
<u></u>
<u> Step(ii):-</u>
Given that A and B are independent events
P(A∩B) =P(A) P(B)
<u></u>
