Factor is the numbers that divides another number or expression without the remainder. For example, 3 and 6 are factors of 12 because 12÷ 3=4 and 12÷6=2.
Answer:
a) 17.5
b) 15.6
c) 13.3
d) 21.51
Step-by-step explanation:
The given function is equal to:
f(x)=kx^2
where

where y=23
Clearing k=0.00025
a) 
b)
c) The function is equal to:
f(x)=k(1+2x)

where y=20
k=0.0024

d) 
In 2 hours,hope this helps :)
we know that
1 ft--------> is equals to 12 in
the ramp is 12 inches tall----------> 1 ft tall
A ramp measures------------------> 6 ft long
applying the Pythagorean theorem
c²=a²+b²
where
c-----> 6 ft long
a----> horizontal distance
b-----> 1 ft tall
a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft
the answer is
5.92 ft
Answer:
x = -1 and y = 1
Step-by-step explanation:
5x + 2y = -3 . . . . . . . (i)
x + 5y = 4 . . . . . . . (ii)
- Finding x in terms of y from eq. (ii) :-
x + 5y = 4
x = 4 - 5y
- Placing this value of x in eq. (i) :-
5(4 - 5y) + 2y = -3
20 - 25y + 2y = -3
-23y = - 23
<u>y = 1</u>
- Placing the value of y in eq. (i)
5x + 2(1) = -3
5x + 2 = -3
5x = - 5
<u>x = -1</u>