Answer:
If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?
Step-by-step explanation:
First of all, when you want to contrast two hypothesis you need a confidence level p% without which the comparison makes no sense.
In this case, you want to refuse the null hypothesis (the average is 5%) with an alternative one (the average is less than 5%).
You propose a new average (3.6%) based on the evidence.
You cannot prove that the average is actually 3.6%, <em>but if you somehow determine that the probability the average is greater than 3.6% is lower than 100% minus your confidence level p% ,then you can refute the null hypothesis and accept the alternative one as new average.
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So, from the possible choices, the one that fits the best is
If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?
Answer:
In 3.75 years, you will have $865.30
Step-by-step explanation:
Answer:
Worked 5 hours: $550
Worked 7 hours: $2,750
Worked 12 hours: $6,600
Step-by-step explanation:
5+7+12=24
13200/24 = 550
(5)*(550) = 2,750
(7)*(550) = 3,850
(12)*(550) = 6,600
