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Andrew [12]
3 years ago
14

What is the meaning for science?

Computers and Technology
1 answer:
ELEN [110]3 years ago
5 0
Science is the special kind of knowledge.Science is the special kind of knowledge related to nature and natural phenomena.
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Identify the following as True or False.
Leni [432]

Answer:

The answer to this question as follows:

1) False

2) False

3) True

Explanation:

The description of the above option as follows

  • In option 1, A single character variable must be contained in one quote mark, but it is based on the alphabet, which is a specific device, and the price of a continued character varies from one device to another, that's why it is false.
  • In option 2, This option is wrong because in assembly language the identifier value must not exceed the length than 247 characters.
  • In option 3, It is correct because in the variable declaration the first char should be a letter, _, @ or $letter. A total of 1-247 characters. The default case is insensitive.

5 0
3 years ago
The objects that you place on master pages are called _____.
Studentka2010 [4]
The answer to this is A.
3 0
3 years ago
Which button is used to open the Start menu in Windows Vista?
Karo-lina-s [1.5K]
The answer is B. Windows icon
4 0
4 years ago
The Caesar Cipher has 25 different shifts to try.
statuscvo [17]

Answer:

D. 25x24x23x22x21.....3x2x1.

Explanation:

The ceasar cipher is a encryption technique, that uses a combination of information or keys to encrypt an information.

The 25 shift ceasar cipher has 25 different combinations, so the number of probable random cipher substitution is 25!,

That is = 25 × 24×23× 22×..... ×2×1.

3 0
3 years ago
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
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