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3 years ago

At the supermarket you can fill your own honey bear container. A customer buys 12 oz of honey for $5.40.

Mathematics

1 answer:

Snezhnost [94]3 years ago

7 0

Answer:

a cumshot

Step-by-step explanation:

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The amount of snowfall falling in a certain mountain range is normally distributed with a mean of 89 inches comma89 inches, and

polet [3.4K]

sorry wish I could help but iI forgot all this:(

4 0

3 years ago

What is the value of y in the equation, 4(2y+1)=2(y-13)

Alik [6]

I hope this helps you

4 0

3 years ago

In the 30-60-90 triangle below, side s has a length of _____ and side q has a length of _____.

Slav-nsk [51]

In a 30-60-90 triangle, the side lengths are in the ratio 1:2:sqrt(3) = short leg: hypotenuse: long leg.

We know the hypotenuse is 8. We can use this to find the other legs.

The short leg s is 8/2 = 4 because the short leg is always half of the hypotenuse.

The long leg q is 4 * sqrt(3), because the long leg is always sqrt(3) times the shorter leg.

So:

s = 4

q = 4 * sqrt(3)

6 0

3 years ago

Read 2 more answers

Use trigonometric substitution to evaluate the integral 13 + 12x − x2 dx . First, write the expression under the radical in an a

SCORPION-xisa [38]

I don't see a square root sign anywhere, so I'll assume the integral is

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx$

First complete the square:

$13+12x-x^2=49-(6-x)^2=7^2-(6-x)^2$

Now in the integral, substitute

$6-x=7\sin t\implies\mathrm dx=-7\cos t\,\mathrm dt$

so that

$t=\sin^{-1}\left(\dfrac{6-x}7\right)$

Under this change of variables, we have

$7^2-(6-x)^2=7^2-7^2\sin^2t=7^2(1-\sin^2t)=7^2\cos^2t$

so that

$\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx=-7\int\sqrt{7^2\cos^2t}\,\cos t\,\mathrm dt=-49\int|\cos t|\cos t\,\mathrm dt$

Under the right conditions, namely that cos(<em>t</em>) > 0, we can further reduce the integrand to

$|\cos t|\cos t=\cos^2t=\dfrac{1+\cos(2t)}2$

$\displaystyle-49\int|\cos t|\cos t\,\mathrm dt=-\frac{49}2\int(1+\cos(2t))\,\mathrm dt=-\frac{49}2\left(t+\frac12\sin(2t)\right)+C$

Expand the sine term as

$\dfrac12\sin(2t)}=\sin t\cos t$

Then

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \sin t=\dfrac{6-x}7$

$t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \cos t=\sqrt{7^2-(6-x)^2}=\sqrt{13+12x-x^2}$

So the integral is

$\displaystyle-\frac{49}2\left(\sin^{-1}\left(\dfrac{6-x}7\right)+\dfrac{6-x}7\sqrt{13+12x-x^2}\right)+C$

3 0

3 years ago

LMNO is a parallelogram. If NM = x + 33 and OL = 4x + 9, find the value of x and then find NM and OL.

anyanavicka [17]

Because these are on opposite sides of the parallelogram, x + 33 = 4x + 9.

This gives you x = 8; OL = 41, NM = 41.

7 0

3 years ago