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3 years ago

Mr. F is buying 8 computers for the computer lab. if one computer costs $1,156, How much will the computers cost in all?

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

answer: $9248

explanation:

well, we know the cost for one, so if each computer costs the same, multiply the cost of one of them by 8 to get the total.

8 x 1,156 = 9248.

so, we can assume this is what the computers will cost in total because there seems to be no added tax or fees.

<em>i hope this helps, and have a great day! don't hesitate to ask if you need more help with this specific question! ♥ - eviezoom </em>

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Answer:

a) 0.0228 = 2.28% probability of a northward displacement of less than 500 kilometers

b) 0.0808 = 8.08% probability of a northward displacement of less than 500 kilometers

c) 1200 kilometers, because in this case, the will be a higher probability of a northward displacement that is less than 500 kilometers.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Standard deviation of 500 kilometers

This means that $\sigma = 500$

a. Assuming the mean is 1500 kilometers, what is the probability of a northward displacement of less than 500 kilometers?

Mean of 1500 km means that $\mu = 500$

The probability is the pvalue of Z when X = 500. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 1500}{500}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

0.0228 = 2.28% probability of a northward displacement of less than 500 kilometers.

b. Assuming the mean is 1200 kilometers, what is the probability of a northward displacement of less than 500 kilometers?

Now $\mu = 1200$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 1200}{500}$

$Z = -1.4$

$Z = -1.4$ has a pvalue of 0.0808

0.0808 = 8.08% probability of a northward displacement of less than 500 kilometers.

c. If, in fact, the northward displacement is less than 500 kilometers, which is the more plausible mean, 1200 or 1500 kilometers?

1200 kilometers, because in this case, the will be a higher probability of a northward displacement that is less than 500 kilometers.

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Not much can be done without knowing what $\mathbf F(x,y,z)$ is, but at the least we can set up the integral.

First parameterize the pieces of the contour:

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where $0\le t_1\le\dfrac\pi2$ and $0\le t_2\le1$ . You have

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and so the work is given by the integral

$\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r$
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This isn't a math question and should be in the science section. However, I will still answer the question. The answer is choice B.

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Here's a further breakdown

A. False. The radiation or energy from the sun can travel through air or else you wouldn't feel the sun's rays. Also, plant life wouldn't be alive without that energy going through the air.

B. True. The rays travel through a vacuum of space. If they couldn't travel through space, then the same problem comes up as in choice A: the issue of not feeling the sun's rays.

C. False. They rays have different frequencies. Because there are many wavelengths (see choice D below), this means there are different frequencies. Recall that f = 1/w where f is the frequency and w is the wavelength.

D. False. The rays are made of different wavelengths. The visible light portion is what we can see, though there is a lot more to the electromagnetic spectrum (eg: ultraviolet light).

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So once again, the answer is choice B

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